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question about chr

Posted on 1998-11-26
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Last Modified: 2010-04-04
I am using Delphi 3 and have 2 edit boxes on the screen and 1 button.

In 1 edit box, I type lower case alphabet only words.  When I press the button, I take each character 1 at a time, and add 1 to the ordinal value of the character.  (Up to this point, this works fine)

Then I want to store each 'new' character into a string variable with a statement like this:  var output:string;
                                          input:string;
                                          x:integer;
  x:=ord(input[i]);
  x:=x+1;
  output:=chr(x);  <-- this is the line that the compiler keeps on saying that there is an error.
What am I doing wrong?

Thanks

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Question by:psabourin
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scrapdog earned 50 total points
ID: 1348167
The problem is that you are trying to store a char in a string variable.  These are two different types.

One solution would be to use concatenation.

x:=ord(input[i]);
  x:=x+1;
  output := '';
  output := output + chr(x);  


Or you could set one of the chars in the string directly.

Like this:

x := ord(input[i]);
  SetLength(s,1);
  s[1] :=chr(x);


I don't know what exactly your purpose is, but I would suggest something like this:

output := '';
for i := 1 to length(input) do begin
  x:=ord(input[i]);
  x:=x+1; if x>255 then x := 0;
  output := output + chr(x);
end;

Output will be contain a string of characters, all 1 greater than the corresponding character in input.


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by:scrapdog
ID: 1348168
Or, even better, you could possibly do this:

output := '';
for i := 1 to length(input) do
  output := output + succ(input[i]);

where you can avoid changing to an integer altogether.
(succ is the successor function, an ANSI pascal function.  Check your help file on it for more details.)

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LVL 27

Expert Comment

by:kretzschmar
ID: 1348169
hi psabourin,

your OutputVar is a string and you will place there a Char, thats incompatibel.

When the Output holds only a Char you can use

Output := '';
Output := Output + Chr(X);

When Output holds the InputString manipulated each Char Increased by one then
only

Output := Output + Chr(X);

To manipilulate the whole InputString to OutputString
Use

Output := '';
For I := 1 to Length(Input) do Output := Output + Chr(Ord(Input[I])+1);


Meikl

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Author Comment

by:psabourin
ID: 1348170
Thanks
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LVL 27

Expert Comment

by:kretzschmar
ID: 1348171
wow, this q was from nov '98
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Author Comment

by:psabourin
ID: 1348172
Sorry, got tied up with other stuff.  I meant to do this a long time ago.  But better late than never, I suppose!
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