Here is the problem: I got these values: FromDate, ToDate, DayFrom, DayTo, EveningFrom, EveningTo, NightFrom, NightTo.

FromDate and ToDate are date/time values going over multiple days. Dayfrom, dayto, eveningFrom, eveningto, nightfrom, nightto are time values defining a period of the day( Day: 08:00 - 14:59, Evening: 15:00-20:59, Night: 21:00-07:59).

I need to calculate how many minutes day, evening and night the fromdate-todate contain.

Anyone know of a function like that?

Mr. Fixit

FromDate and ToDate are date/time values going over multiple days. Dayfrom, dayto, eveningFrom, eveningto, nightfrom, nightto are time values defining a period of the day( Day: 08:00 - 14:59, Evening: 15:00-20:59, Night: 21:00-07:59).

I need to calculate how many minutes day, evening and night the fromdate-todate contain.

Anyone know of a function like that?

Mr. Fixit

ex : nMinutes = DateDiff("n", FromDate, ToDate)

Now, you can convert those minutes for your needs.

Here is the help :

Syntax

DateDiff(interval, date1, date2[, firstdayofweek[, firstweekofyear]])

The DateDiff function syntax has these named arguments:

Part Description

interval Required. String expression that is the interval of time you use to calculate the difference between date1 and date2.

date1, date2 Required; Variant (Date). Two dates you want to use in the calculation.

firstdayofweek Optional. A constant that specifies the first day of the week. If not specified, Sunday is assumed.

firstweekofyear Optional. A constant that specifies the first week of the year. If not specified, the first week is assumed to be the week in which January 1 occurs.

Settings

The interval argument has these settings:

Setting Description

yyyy Year

q Quarter

m Month

y Day of year

d Day

w Weekday

ww Week

h Hour

n Minute

s Second

The firstdayofweek argument has these settings:

Constant Value Description

vbUseSystem 0 Use the NLS API setting.

vbSunday 1 Sunday (default)

vbMonday 2 Monday

vbTuesday 3 Tuesday

vbWednesday 4 Wednesday

vbThursday 5 Thursday

vbFriday 6 Friday

vbSaturday 7 Saturday

The firstweekofyear argument has these settings:

Constant Value Description

vbUseSystem 0 Use the NLS API setting.

vbFirstJan1 1 Start with week in which January 1 occurs (default).

vbFirstFourDays 2 Start with the first week that has at least four days in the new year.

vbFirstFullWeek 3 Start with first full week of the year.

Remarks

You can use the DateDiff function to determine how many specified time intervals exist between two dates. For example, you might use DateDiff to calculate the number of days between two dates, or the number of weeks between today and the end of the year.

To calculate the number of days between date1 and date2, you can use either Day of year ("y") or Day ("d"). When interval is Weekday ("w"), DateDiff returns the number of weeks between the two dates. If date1 falls on a Monday, DateDiff counts the number of Mondays until date2. It counts date2 but not date1. If interval is Week ("ww"), however, the DateDiff function returns the number of calendar weeks between the two dates. It counts the number of Sundays between date1 and date2. DateDiff counts date2 if it falls on a Sunday; but it doesn't count date1, even if it does fall on a Sunday.

If date1 refers to a later point in time than date2, the DateDiff function returns a negative number.

The firstdayofweek argument affects calculations that use the "w" and "ww" interval symbols.

If date1 or date2 is a date literal, the specified year becomes a permanent part of that date. However, if date1 or date2 is enclosed in double quotation marks (" "), and you omit the year, the current year is inserted in your code each time the date1 or date2 expression is evaluated. This makes it possible to write code that can be used in different years.

When comparing December 31 to January 1 of the immediately succeeding year, DateDiff for Year ("yyyy") returns 1 even though only a day has elapsed.

1) StartTime to End of the day (Some date but different time)

2) Couple of complete days

3) Begin of the day to End date (Some date different time)

The second once is easy to calculate since these are complete days. The other ones are more difficult and should use datediff.

Replace the time with the end time of your time zone and use datediff.

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