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Open Text File of Numbers into an Array

Posted on 1998-12-06
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Last Modified: 2010-04-02
I have a text file with a header row of variables and the rest as numbers in columns.  I can open the file using getline but it reads the number rows as a string.  What I then have to do is break each string of row numbers down by looking for tab spaces, converting the string to a number, and then saving it into an array.  Can somebody please tell me the easiest way to open a text file of numbers with various rows and columns into an array?

Thanks
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Question by:dmontgom
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3 Comments
 
LVL 5

Expert Comment

by:yonat
ID: 1179457
int i;
while (cin >> i) {
    // do stuff with i
}

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LVL 22

Expert Comment

by:nietod
ID: 1179458
i.e what yonat is saying is that the standard library is capable of reading the ASCII data and converting the digits into integers (or other numerical types)  so don't read the data in as ASCII characters, read it in as the numerical type you want.
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Accepted Solution

by:
billyh earned 100 total points
ID: 1179459
Hope this helps:

#include "fstream.h"
#include "iostream.h"

#ifndef MAXLEN
      #define MAXLEN 45
#endif

void main()
{
      char header_row[MAXLEN];
      fstream in_text_file;
      int local_var = 0, index = 0, int_arr[MAXLEN];

      in_text_file.open("text.dat",ios::in);

      while(!in_text_file.eof())
      {
            if (!local_var)
            {
                  in_text_file.getline(header_row,MAXLEN,'\n');
                  ++local_var;
            }
            else
            {
                  in_text_file >> local_var;
                  int_arr[index] = local_var;
                  ++index;
            }
      }

      in_text_file.close();
}
0

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