Solved

Days

Posted on 1998-12-07
3
186 Views
Last Modified: 2010-05-18
I want to make a program to count a total days, examples i saved 01-31-98 (mm/dd/yy) then if today is 01-01-99 (mm/dd/yy) the program count a total days from 01-31-98. so the output from the program will be 1 days.
others examples, i save 02-01-99 then i input 03-01-99 then the outpun must be 28 days.. the output must be in days!!
Thanks
0
Comment
Question by:ichen
  • 2
3 Comments
 
LVL 1

Accepted Solution

by:
flivauda earned 100 total points
ID: 1206783
#!/usr/local/bin/perl

$days = &days_since_1990(1998, 3, 1) -  &days_since_1990(1998, 2, 1);
print "Days: $days\n";


sub leap_year
{
        local($year); $year = shift;
        local($x);
        $x = ((($year % 4 == 0) && ($year % 100 != 0)) || ($year % 400 ==0));
        return $x;
}

sub days_in_year
{
        local($year); $year = shift;
        return (&leap_year($year) ? 366 : 365);
}

sub days_in_month
{
        local($year); $year = shift;
        local($month); $month = shift;
        @days_per_month = (31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);

        if (($month<1) || ($month>12))
        {

                $days=0;
        }
        else
        {
                $days = $days_per_month[$month - 1];
                if (&leap_year($year) && ($month == 2))
                {
                        $days++;
                }
        }
        return $days;
}

sub day_of_year
{
        $year = shift;
        $month = shift;
        $day = shift;
        local($x);
        local($day_count);

        $day_count=0;
        for ($x=1;$x<$month;$x++)
        {
                $day_count += &days_in_month($year, $x);
        }
        return ($day_count + $day);
}

sub days_since_1990
{
        local($year); $year = shift;
        local($month); $month = shift;
        local($day); $day = shift;
        local($x);
        local($day_count);

        $day_count=0;

        if ($year<1990)
        {
                return 0;
        }

        for ($x=1990;$x<$year;$x++)
        {
                $day_count += &days_in_year($x);
        }
        $day_count += &day_of_year($year, $month, $day) - 1;

        return $day_count;
}


0
 
LVL 84

Expert Comment

by:ozo
ID: 1206784
sub days_since_1990 { use Time::Local; (timegm(0,0,0,$_[2],$_[1]-1,$_[0]-1900)-timegm(0,0,0,1,1-1,1990-1900)) / (60*60*24) }
0
 
LVL 1

Expert Comment

by:flivauda
ID: 1206785
I just ported over my old C code, your is a little shorter =)
0

Featured Post

Announcing the Most Valuable Experts of 2016

MVEs are more concerned with the satisfaction of those they help than with the considerable points they can earn. They are the types of people you feel privileged to call colleagues. Join us in honoring this amazing group of Experts.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

A year or so back I was asked to have a play with MongoDB; within half an hour I had downloaded (http://www.mongodb.org/downloads),  installed and started the daemon, and had a console window open. After an hour or two of playing at the command …
Checking the Alert Log in AWS RDS Oracle can be a pain through their user interface.  I made a script to download the Alert Log, look for errors, and email me the trace files.  In this article I'll describe what I did and share my script.
Explain concepts important to validation of email addresses with regular expressions. Applies to most languages/tools that uses regular expressions. Consider email address RFCs: Look at HTML5 form input element (with type=email) regex pattern: T…
Windows 10 is mostly good. However the one thing that annoys me is how many clicks you have to do to dial a VPN connection. You have to go to settings from the start menu, (2 clicks), Network and Internet (1 click), Click VPN (another click) then fi…

813 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

10 Experts available now in Live!

Get 1:1 Help Now