Disable Start button

Posted on 1998-12-10
Last Modified: 2010-07-27
I found this code thats supposed to disable enable the start button but it does not work. What is wrong or I need code that works.

'to disable
Call EnableWindow(FindWindowEx(FindWindow("Shell_TrayWnd", ""), vbNull, "Button", ""), False)

'to enable
 Call EnableWindow(FindWindowEx(FindWindow("Shell_TrayWnd", ""), vbNull, "Button", ""), True)
This is the start button with the windows logo on the taskbar, and the keyboard.

Thank you Experts
Question by:fred12

Expert Comment

ID: 1449225
Tray this:

Dim hWnd1 As Long

Declare Function FindWindow Lib "user32" Alias "FindWindowA" (ByVal lpClassName As String, ByVal lpWindowName As String) As Long

Declare Function SetWindowPos Lib "user32" (ByVal hwnd As Long, ByVal hWndInsertAfter As Long, ByVal x As Long, ByVal y As Long, ByVal cx As Long, ByVal cy As Long, ByVal wFlags As Long) As Long
       Const SWP_HIDEWINDOW = &H80
       Const SWP_SHOWWINDOW = &H40

'code for disable:
hWnd1 = FindWindow("Shell_traywnd", "")
Call SetWindowPos(hwnd1, 0, 0, 0, 0, 0, SWP_HIDEWINDOW)

'and code for enable again:
Call SetWindowPos(hwnd1, 0, 0, 0, 0, 0, SWP_SHOWWINDOW)


Author Comment

ID: 1449226
Dalin sorry the code you provided hide/shows all of taskbar, Im looking for just the start button. Thank you
LVL 13

Accepted Solution

Mirkwood earned 100 total points
ID: 1449227
Here you are:

Private Declare Function FindWindow Lib "user32" Alias "FindWindowA" (ByVal lpClassName As String, ByVal lpWindowName As String) As Long
Private Declare Function FindWindowEx Lib "user32" Alias "FindWindowExA" (ByVal hWnd1 As Long, ByVal hWnd2 As Long, ByVal lpsz1 As String, ByVal lpsz2 As String) As Long
Private Declare Function EnableWindow Lib "user32" (ByVal hwnd As Long, ByVal fEnable As Long) As Long

Private Sub Command1_Click()
'to disable
Call EnableWindow(FindWindowEx(FindWindow("Shell_TrayWnd", ""), 0, "Button", ""), 0)

End Sub

Private Sub Command2_Click()
'to enable
Call EnableWindow(FindWindowEx(FindWindow("Shell_TrayWnd", ""), 0, "Button", ""), 1)
End Sub


Expert Comment

ID: 1449228
Try this:
Dim hFw as long
hFw = FindWindow("Shell_TrayWnd", vbNullString)
hFw = FindWindowEx(hFw, 0,  "Button", vbNullString)
EnableWindow(hFw, FALSE)

Author Comment

ID: 1449229

Featured Post

3 Use Cases for Connected Systems

Our Dev teams are like yours. They’re continually cranking out code for new features/bugs fixes, testing, deploying, testing some more, responding to production monitoring events and more. It’s complex. So, we thought you’d like to see what’s working for us.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
Saving history changes to sub form 4 43
Copy a row 12 62
VB6 - Convert HH:MM into Decimal 8 56
Automatic Email Reminder 4 38
Most everyone who has done any programming in VB6 knows that you can do something in code like Debug.Print MyVar and that when the program runs from the IDE, the value of MyVar will be displayed in the Immediate Window. Less well known is Debug.Asse…
Enums (shorthand for ‘enumerations’) are not often used by programmers but they can be quite valuable when they are.  What are they? An Enum is just a type of variable like a string or an Integer, but in this case one that you create that contains…
As developers, we are not limited to the functions provided by the VBA language. In addition, we can call the functions that are part of the Windows operating system. These functions are part of the Windows API (Application Programming Interface). U…
Get people started with the utilization of class modules. Class modules can be a powerful tool in Microsoft Access. They allow you to create self-contained objects that encapsulate functionality. They can easily hide the complexity of a process from…

803 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question