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treeview building

Posted on 1998-12-14
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Last Modified: 2010-05-03
i am trying to build a stair tree. i have succeeded in building a root node and a few children with the treeview.nodes.add but for some reason when i try to build a two level tree of questions answers meaning:
q
---a
q
---a
q
---a
as it is writen in the help file, i get a debug msg. that the object is not found. can you write me an example that builds a tree like the example above.
thank you.
p.s i'm using vb6.
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Question by:ilanm
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6 Comments
 
LVL 7

Accepted Solution

by:
Inteqam earned 150 total points
ID: 1450069
insert a treeview in a form and paste the following:

Private Sub Form_Load()
Dim n As Node

Set n = Me.TreeView1.Nodes.Add(, , "root", "root")
Set n = Me.TreeView1.Nodes.Add("root", tvwChild, "q1", "q")
Set n = Me.TreeView1.Nodes.Add("root", tvwChild, "q2", "q")
Set n = Me.TreeView1.Nodes.Add("root", tvwChild, "q3", "q")
Set n = Me.TreeView1.Nodes.Add("q1", tvwChild, "a1", "a")
Set n = Me.TreeView1.Nodes.Add("q2", tvwChild, "a2", "a")
Set n = Me.TreeView1.Nodes.Add("q3", tvwChild, "a3", "a")

End Sub


0
 

Author Comment

by:ilanm
ID: 1450070
thank you for your answer, but i meant a dynamic tree where there could be 100 question answers or 3.
0
 
LVL 7

Expert Comment

by:Inteqam
ID: 1450071
try this
insert a treeview in a form and paste the following:

Private Sub Form_Load()
Dim n As Node
Dim Count as integer
Dim strKeyq as String
Dim strKeta
Set n = Me.TreeView1.Nodes.Add(, , "root", "root")
' use a counter for the Q's
while there is more questions
   count=count+1
   strKeyq="q"+cstr(Count)
   strKeya="a"+Cstr(Count)
 Set n = Me.TreeView1.Nodes.Add("root", tvwChild, strkeyq, "q")
 Set n = Me.TreeView1.Nodes.Add(strkeyq, tvwChild, strkeya, "a")
wend
End Sub

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Author Comment

by:ilanm
ID: 1450072
Inteqam i still get the error msg of object not found.

0
 
LVL 7

Expert Comment

by:Inteqam
ID: 1450073
it works will in my PC ,
where the error happens?

0
 
LVL 7

Expert Comment

by:Inteqam
ID: 1450074
mis spilled Dim strKeta  
it must be Dim strKeya

try now.

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