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Accessing members of an array of structs

Posted on 1998-12-17
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Last Modified: 2013-12-14
I am fairly new to C and I am using a fuction in a DLL whose documentation is:
--------------------
typedef struct
{
int i;
} X_Y

// prototype
bool TheFunc(X_Y **ppUsers;
-------------------
// In arguments none.
// Out returns ppUsers a pointer to the Users array.
-------------------
Now when I debug this with variables watch it returns an pointer to an array of structs.

Question how do I access members of individual structs in the array. Eg if there was 5 structs in the array how do get "int i" from the second struct??

Code example please !!
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Question by:cosmicmike
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RONSLOW earned 50 total points
ID: 1255274
like this...
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Expert Comment

by:RONSLOW
ID: 1255275
something like this

X_Y* pUsers;

pUsers = NULL;
if (TheFunc(&pUsers)) {
  /* guess TheFunc returns true if it allocated an array */
  if (pUsers) { /* check anyway */
    int j;
    int n;
    n = 10; /* how do you know how many in the array? */
    for (j = 0; j < n; j++) {
      printf("%d\n",pUsers[j].i);
    }
    /* you may have to free the array afterwards */
  }
}

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Author Comment

by:cosmicmike
ID: 1255276
RONSLOW
I left an important bit out of the prototype

// prototype
bool TheFunc(&iCount, X_Y **ppUsers;

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Expert Comment

by:RONSLOW
ID: 1255277
that would probably change it to..

X_Y* pUsers;
int n;

pUsers = NULL;
n = 0;
if (TheFunc(&pUsers)) {
  /* guess TheFunc returns true if it allocated an array */
  if (pUsers && n != 0) { /* check anyway */
    int j;
    for (j = 0; j < n; j++) {
      printf("%d\n",pUsers[j].i);
    }
    /* you may have to free the array afterwards */
  }
}

0
 

Author Comment

by:cosmicmike
ID: 1255278
RONSLOW

I would have thought that to access a member from a pointer
would be pUsers->i ?????????
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Expert Comment

by:RONSLOW
ID: 1255279
Not when it is an array.

-> is to derefence a pointer to a single item
[j] is to derefence a pointer to one element of an array of items.

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Expert Comment

by:RONSLOW
ID: 1255280
Not when it is an array.

-> is to derefence a pointer to a single item
[j] is to derefence a pointer to one element of an array of items.

0
 
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Expert Comment

by:RONSLOW
ID: 1255281
Not when it is an array.

-> is to derefence a pointer to a single item
[j] is to derefence a pointer to one element of an array of items.

0
 
LVL 10

Expert Comment

by:RONSLOW
ID: 1255282
oops .. don't know how that happened. It looks like I'm saying everything three times everything three times everything three times :-)

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