Output awk to route delete

Try the folowing simple script:
#!/bin/ksh

netstat -m | awk '{if ($3 == "UGHD") print $1,":",$2 > "output.txt"}'
FIRST=`cut -d: -f1 output.txt`
SECOND=`cut -d: -f2 output.txt`

route delete $FIRST $SECOND

Good luck!
Leandro

Leandro - I forgot to add the stipulation that we do not want to create an intermediate file in the process.  Why won't this command work?

netstat -rn | awk '"UGHD" {system (route delete $1 $2)}'

`netstat -rn | awk '{ if ($3 == "UGHD") print "route delete",$1,$2 }'`

Thanks, Seedy - I tried your command, and it didn't work, but it did put us on the right track.  The use of commas following the route delete command causes an error that there are too many parameters.  Instead, we can use ..."route delete "$1" "$2}' - Unix liked that much better.  The actual command we added to our cron job ended up being: netstat -rn | awk '$3 = /UGHD/ { system("route delete "$1" "$2)}'.

Thanks for leading us in the right direction!

Seedy - I need for you to post the answer so I can award the points!

I think that solution proposed by seedy is not what sharonp wants.
The "route delete $1 $2" should be executed and not printed
My new solution is:

  for i in `netstat -m | awk ´{if ($3 == "UGHD") print $1":"$2}´`
  do
  FIRST=`echo $i | cut -d: -f1`
  SECOND=`echo $i | cut -d: -f2`
  route delete $FIRST $SECOND
  done

  This can be done on command line or script
  It´s simple but i think that works.

  Regards.
  Leandro.