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WIN32  Copying a BITMAP to a new BITMAP

Posted on 1999-01-05
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Last Modified: 2012-08-14
In c/c++ .win32 without using mfc, how can you have a bitmap, and create a new bitmap which contains only a section of the original?

Example:
Original Bitmap 100 X 100 pixels.  I want to create a 20 x 20 bitmap that contains the picture whose top left corner starts at 80,80 on the original bitmap.
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Question by:Cov
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by:Cov
ID: 1113556
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ryanvs earned 80 total points
ID: 1113557
You need to copy the bitmap using BitBlt or StretchBlt to a new bitmap
and memory DC that you create.  Assuming you have an existing Bitmap
handle and DC handle, you would do the following:

HDC hdcMem;           // Memory Device for new bitmap
HBITMAP hbmCopy;      // The new bitmap copy
int xCopyWidth = 20, yCopyHeight = 20;  // New Dimensions
int xWidth = 100, yHeight = 100;  // Original Dimensions
int xStart = 80, yStart = 80;    // Starting Position in Original

hdcMem = CreateCompatibleDC(hdcOrginal);
hbmCopy = CreateCompatibleBitmap(hdcMem, xCopyWidth, yCopyHeight);

SelectObject(hdcMem, hbmCopy);
SetMapMode(hdcMem, GetMapMode(hdcMem));

// Copy Original Bitmap to Bitmap Copy
BitBlt(
        hdcMem,    // Bitmap Copy Memory
        0,         // x Starting Point of Copy
        0,         // y Starting Point of Copy
        xCopyWidth,  // Width of Copy
        yCopyHeight, // Height of Copy
        hdcOriginal, // Device to be copied
        xStart,      // x Starting Point of Source
        yStart,      // y Starting Point of Source
        SRCCOPY);

<....program code....>
// When finished free bitmap and memory space
DeleteObject(hbmCopy);
DeleteDC(hdcMem);


I hope this helps...
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