# Logical & and |

Looking to do some arithmetic operation on a number to clear all the hex-bits of a number except the lower 4. For example:

The number '96237' is equal to the hex value '0001 77ed'. I want to just keep the lower 4 bits which in this case is '77ed'. Hex value '77ed' is 30701, the number I want. Sooo... How can I take the number '96237' (or any number) do some arithemetic to clear all the bits except the last 4, to end up with the value '96237';

\$num = 96237;

HELP!  Thanks so much!!
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Commented:
Thanks.  Did you get \$num |= 0xffff0000 to work?
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Commented:
Logically 'and' the number with 65535.
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Commented:
\$num &= 0xffff;
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Author Commented:
Ozo your idea worked! One more question, sheesh you good at this!

How do I turn on all the high bits?  That is leave the lower four hex bits alone and turn on the upper four hex bits?  for example: \$num_second = 46071

46071 = 0000 B3F7
FFFF B357 = 4294947831

so I want to go from 46071 to 4294947831, via a similar same math operation.
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Commented:
Ozo's answer was the same as mine...oh well.

>How do I turn on all the high bits?  That is leave the lower >four hex bits alone and turn on the upper four hex bits?  for >example: \$num_second = 46071

\$num |= 0xffff0000;

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Commented:
>Ozo's answer was the same as mine...oh well.

This was not meant to criticize ozo...we must have posted at the exact same time, so neither of us had seen each other's posts.  What I meant was that "65535" is the same as "0xffff".
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Author Commented:
whoopsie in that case ya get the points scrappy :) reanswer!
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Commented:
ozo probably gave you the better answer, so if you want to reject and give him/her the points, go ahead...
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Author Commented:
whoopsie in that case ya get the points scrappy :) reanswer!
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Author Commented:
yes
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