Solved

Finding picture box hwnd.

Posted on 1999-01-10
4
408 Views
Last Modified: 2009-12-16
Hello,

I'm painting from one application to other application's
picture box.
I need to know the other application picture box hwnd in order to paint in it (there's more than one picture box in the form and I don't want to pass the hwnd with communication between the application).
If I use FindWindow I can find the form (because I have the form caption) , but picture box have no caption and I don't
know how to find it hwnd.

Any suggestions ?

Thanks
0
Comment
Question by:Amnon
  • 2
4 Comments
 
LVL 1

Expert Comment

by:RichardE
ID: 1455171

You do not indicate which version of VB you are using. This works in VB6 but not sure if VB5 allowed you to create form properties.

If using VB6 : Put the Picture box's HWND in a property of the form.

Create a form level property such as : PicBoxHandle

Then if that form's load event :

PicBoxHandle = Me.Picture1.hWnd  

Now when you "locate" that form from the other app, just check the PicBoxHandle property.



0
 

Author Comment

by:Amnon
ID: 1455172
I'm working with vb4 and can't craete a form level property .
0
 
LVL 3

Accepted Solution

by:
Sendoh earned 100 total points
ID: 1455173
Hi !
I think you can get it by calling

Declare Function EnumChildWindows Lib "user32" Alias "EnumChildWindows" (ByVal hWndParent As Long, ByVal lpEnumFunc As Long, ByVal lParam As Long) As Long

and get the classname of every child window by calling

Declare Function GetClassName Lib "user32" Alias "GetClassNameA" (ByVal hwnd As Long, ByVal lpClassName As String, ByVal nMaxCount As Long) As Long

Just check

if instr(className, "PictureBox") then

will do.

Hope this'll help you.
0
 
LVL 3

Expert Comment

by:Sendoh
ID: 1455174
The code as follow :

Declare Function GetClassName Lib "user32" Alias "GetClassNameA" (ByVal hwnd As Long, ByVal lpClassName As String, ByVal nMaxCount As Long) As Long
Declare Function EnumChildWindows Lib "user32" (ByVal hWndParent As Long, ByVal lpEnumFunc As Long, ByVal lParam As Long) As Long

Function enumChildProc(ByVal hwnd As Long, ByVal lParam As Long) As Boolean
    Dim abc As String * 100
   
    GetClassName hwnd, abc, 100
    If InStr(abc, "PictureBox") Then
        MsgBox abc
        enumChildProc = False
    Else
        'MsgBox Str(hwnd)
        enumChildProc = True
    End If
End Function

Private Sub Command1_Click()
    EnumChildWindows Form1.hwnd, AddressOf enumChildProc, &H0
End Sub

0

Featured Post

Optimizing Cloud Backup for Low Bandwidth

With cloud storage prices going down a growing number of SMBs start to use it for backup storage. Unfortunately, business data volume rarely fits the average Internet speed. This article provides an overview of main Internet speed challenges and reveals backup best practices.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

When designing a form there are several BorderStyles to choose from, all of which can be classified as either 'Fixed' or 'Sizable' and I'd guess that 'Fixed Single' or one of the other fixed types is the most popular choice. I assume it's the most p…
Enums (shorthand for ‘enumerations’) are not often used by programmers but they can be quite valuable when they are.  What are they? An Enum is just a type of variable like a string or an Integer, but in this case one that you create that contains…
As developers, we are not limited to the functions provided by the VBA language. In addition, we can call the functions that are part of the Windows operating system. These functions are part of the Windows API (Application Programming Interface). U…
Show developers how to use a criteria form to limit the data that appears on an Access report. It is a common requirement that users can specify the criteria for a report at runtime. The easiest way to accomplish this is using a criteria form that a…

773 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question