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Search in UNIX; a simple question

Posted on 1999-01-12
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Last Modified: 2013-12-06
New to UNIX.

I need to search for  this text;
'/u1/xxx/yyyy' in all the scripts residing in the system.

used the following command:

find . -type f -print | xargs grep -l -i '/u1/xxx/yyyy*'

Returned too many files.

is there any way I can exclude the files with extension '.log' and '.trc'
Looking for the command or a easy way to do this. It's AIX 4.2.

Thanks for the help.
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Question by:iqbalj
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6 Comments
 

Expert Comment

by:christg
ID: 2008703
I don't remember if it's good but you can try:
cd /
find . -print | grep '/u1/xxx/yyyy'
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Author Comment

by:iqbalj
ID: 2008704
Edited text of question
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Author Comment

by:iqbalj
ID: 2008705
Edited text of question
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Expert Comment

by:ozo
ID: 2008706
find . -type f \! -name '*.log' \! -name '*.trc'
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Accepted Solution

by:
rajanxyz earned 100 total points
ID: 2008707
Use the following find command.  It will work.

First cd /
Then

find . -type f ! -name "*.log" ! -name "*.trc" -exec grep -i -l "/u1/xxx/yyyy*" \{\} \;


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Author Comment

by:iqbalj
ID: 2008708
It is now listing all the files (even the Jpegs); I added  '-print' ; Now it looks like this

find . -type f ! -name "*.log" ! -name "*.trc"- print  -exec grep -i -l "/u1/app/oracle*" \{\} \;

I also get this error for some files:

grep: 0652-226 Maximum line length of 2048 exceeded
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