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converting decimal to hex in a ksh script

In a KSH script, I need to take an IP address and convert it to host long, which is a HEX format.
for example: 10.10.20.21 in hex is 168432661
Is there an easy wasy to do this?
Thanks in advance!
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jwcorbett
Asked:
jwcorbett
1 Solution
 
ahoffmannCommented:
for the result in your question (which is decimal not hex):
    echo 10.10.20.21 | awk -F. '{printf "0x%x", ($1*256*256*256)+($2*256*256)+($3*256)+$4;}
or if you want hex:
    echo 10.10.20.21 | awk -F. '{printf "0x%x", ($1*256*256*256)+($2*256*256)+($3*256)+$4;}
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ahoffmannCommented:
first one should read:
   echo 10.10.20.21 | awk -F. '{print $1*256*256*256)+($2*256*256)+($3*256)+$4;}
sorry.
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jwcorbettAuthor Commented:
Thank you!
It works, with a little change in syntax, but for an IP of 10.10.20.21, I get an answer 168433e+08
How can I format the naswer to give the whole number?

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ozoCommented:
awk -F. '{printf "%d",($1*256*256*256)+($2*256*256)+($3*256)+$4;}'
 awk -F. '{printf "%08x",($1*256*256*256)+($2*256*256)+($3*256)+$4;}'
But this may fail for 128.10.20.21
perl -ne 'printf"%08x",unpack"N",pack"C*",split/\./'
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ahoffmannCommented:
echo 128.10.20.21 | awk -F. '{printf "%12.12d",($1*256*256*256)+($2*256*256)+($3*256)+$4;}'

works for me, but depending on your OS leading chars are blanks or zeros

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mliberiCommented:
You can do the whole job without using awk or perl:

#!/bin/ksh
IFSsave=$IFS
typeset -i a b c d     # declare fields to be integer
IFS='.'
echo 10.10.20.21 | read a b c d
IFS=$IFSsave

echo $(((a<<24)+(b<<16)+(c<<8)+d))
# if a>127 the result will be a negative number
exit



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