<div>
See <a href="http://www.dogma.demon.co.uk/codelib/comctl/comctlv.htm" rel="ugc">http://www.dogma.demon.co.uk/codelib/comctl/comctlv.htm</a>&nbsp;for<br />
code<br />
<br />

</div>


See http://www.dogma.demon.co.uk/codelib/comctl/comctlv.htm [http://www.dogma.demon.co.uk/codelib/comctl/comctlv.htm] for
code



<div>
See also the version info classes at <br />
<a href="http://www.mvps.org/vb/samples.htm" rel="ugc nofollow">http://www.mvps.org/vb/samples.htm</a><br />

</div>


See also the version info classes at
http://www.mvps.org/vb/samples.htm [http://www.mvps.org/vb/samples.htm]


<div>
Mirkwood: Not what I needed, sorry.<br />
<br />
I need a function which I give the filename and which then extracts the file's version number.<br />
I do not want to load the DLL (I dont think I can load an EXE).<br />
<br />
<br />

</div>


Mirkwood: Not what I needed, sorry.

I need a function which I give the filename and which then extracts the file's version number.
I do not want to load the DLL (I dont think I can load an EXE).




<div>
Very good answer thank you!!!!<br />

</div>


<div>
<div class="content wysiwyg-content">
How do I get the file version info for an OCX, EXE or DLL.<br />
Is this the version resource?<br />
Is there a simple way to do this.<br />
Points will be awarded for an answer containing a routine that does this, I need code.<br />

</div>
</div>


How do I get the file version info for an OCX, EXE or DLL.
Is this the version resource?
Is there a simple way to do this.
Points will be awarded for an answer containing a routine that does this, I need code.


File version info

Visual Basic is Microsoft’s event-driven programming language and integrated development environment (IDE) for its Component Object Model (COM) programming model. It is relatively easy to learn and use because of its graphical development features and BASIC heritage. It has been replaced with VB.NET, and is very similar to VBA (Visual Basic for Applications), the programming language for the Microsoft Office product line.