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Referring to Items in a list

In LotusScript, I have a list variable set up.  I can use a forall loop to return each of the "keys" of the list, but code like this does not seem to work:

Forall element in MyList
    msgbox element & " = " & MyList(element)
End Forall

What am I doing wrong here?
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IsleOfView
Asked:
IsleOfView
1 Solution
 
fulscherCommented:
Lists appear to contain variants. I never really succedeed to get them to work properly, so I used an array of variable size. You might want to try something like

Forall element in MyList
    msgbox element & " = " & MyList(element)(0)
End Forall

Do you get an error message? Or just an empty response?
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phooeyCommented:
The code you need to use is:

Kount = 0
Forall element in MyList
    msgbox Kount & " = " & MyList(Kount)
    Kount = Kount + 1
End Forall

The reason for this is that the Forall Loop simply does 'something' in the loop for the number of times that there is an element in the list.  Unless you give a delimeter of some kind to say where you are up to in the list )(in this case Kount) you have no way of controlling the list.
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IsleOfViewAuthor Commented:
Phooey:  That doesn't work.  That code gives this error: "List Item Does Not Exist".  I assume this is because you cannot refer to elements of a list variable by their subscript, as in an array.

The code that I used originally would work if I didn't try to include the value (MyList(element)).

fulscher:  This list variable was declared as a string (Dim MyList List as String).  It is the return value of a function, so the function returns a variant that contains this list variable (you can't make a list variable a return value unless it is in a variant container)

I know that the elements of this list variable are available when they are returned, as I can explicitly return each one (i.e., MyList("FirstName") = Joe).  The problem is that this needs to be generic, where the script doesn't know what kind of input it is going to be receiving.
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MrGrinchCommented:
It all depends on what type of object you are returning.
For Example, if you are doing a Forall Loop on a NotesDocumentCollection, you would be returning individual NotesDocuments.  Your MsgBox wants a string, so you could never show a NotesDocument in a MsgBox.  You could, however pull an element from that NotesDocument such as:
Forall x in NotesDocumentCollection
   MsgBox "Form Name: " + x.Form(0)
End Forall
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IsleOfViewAuthor Commented:
This is a list variable, declared as a string, that is returned in a variant container.  (please take a look at my comments below)
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phooeyCommented:
I *think* see the problem now, it is because you are using a defined list.
Try

Forall element in MyList
    currentTag = ListTag(MyList)
    msgbox element & " = " & MyList(CurrentTag)
End Forall

Note: you might need a (0) at the end of the MsgBox line
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phooeyCommented:
OOOPS Screwed that u !!!
Should read

Forall element in MyList
    currentTag = ListTag(element)
    msgbox element & " = " & MyList(currentTag)
End Forall

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IsleOfViewAuthor Commented:
Thanks!  The syntax was just a bit off, but it got me on the right track.  Here's what ended up really working:

Forall element In MyList
    currentTag = Listtag(element)
    Msgbox currentTag & " = " & MyList(currentTag)
End Forall
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