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C (under Unix) programming

How do I pass an argument(a string in particular) to a C program? I would like to run the program by calling its name and the string argument eg "client savuti"; where 'client' is the program name and 'savuti' the argument being passed. In fact the argument I want to pass is a server name or IP address of the server. Please help!
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galeboe
Asked:
galeboe
1 Solution
 
rbrCommented:
use
int main (int argn, char *argv[])
{
     int i;

     printf ("Name: %s\n",argv[0]);
     for (i=1;i<argn;i++)
         printf ("Parameter %d:%s\n",i,argv[i]);
     return(0);
}

argn are the number of parameters+1 since the name of the programm is passed at argv[0]
argv[1] is the first parameter
argv[2] is the second and so on.  
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