What's the difference between "override" and "overload"?

What's the difference between "override" and "overload"?
jhoonAsked:
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Seeker092397Connect With a Mentor Commented:
Override example:

class A
{
public:
  A()
  {
    m_nVal = 0;
  }
  void Foo()
  {
    m_nVal = 1;
  }

  int m_nVal;
};

class B : public A
{
public:
  B() : A()
  {}
  void Foo()
  {
    m_nVal = 2;
  }
};

Class B overrides function Foo(). So now calling
B b;
b.Foo();
will set m_mVal to 2 instead of 1.

You do overriding only if you need to. I mean, if your B class is pretty happy with the way A handles Foo() it shouldn't override it(shouldn't define Foo in its class definition) and still you will be able to call b.Foo() but in this case m_nVal will get value 1.

Hope this helps.

Best regards.
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Seeker092397Commented:
The difference i think is in following:

Override is about inheritence: Overriden function is the function defined in both base and derived classes in exactly the same way, it lets you change the bahaviour of base class.

Overload is about the number of functions with the same name: This way you can define a number of functions in one class with the same name but different parameter types.

Hope this helps.
Best regards.
0
 
nietodCommented:
That's it.    Why don't you answer, seeker?

The way I think about it is that a derived class can provide a finction that overides (changes the behaviour) of a base class's function..  And that two functions with the same and different parameters are overloaded with posibilities.  


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jhoonAuthor Commented:
Thank you so much.

Now I know "overload" which enable a program to have polymorphism.

but I'm not clear about "override".

Would you tell me more about "override" including a simple sample code?
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nietodCommented:
>>Now I know "overload" which enable a program to have polymorphism
No, it is "overide" that provides polymorphism.  Consider a class heirarchy for shapes.  You may have a base class called "Shape", add derive three classes from it for "Circle" "Rectangle", and "Triangle".  Shape may provide a virtual procedure called "Draw()" that is supposed to draw the shape.  (But in the shape class the procedure does nothing, since shape is an abstract class and there is no shape associated with it.)  Each of the derived classes OVERRIDE this procedure to draw their own shapes.   This is polymorphism.  The Shape() function has polymorphic behavior--it acts differently for different classes--because it was overidden.
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jhoonAuthor Commented:
Thank you seeker.

You got rid of my ambiguity.

Thanks again.
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