mraible
asked on
New Line in Javascript Alert
I'm writing out some javascript code in my
servlet, and if I put a "\n" into my code -
I get a undetermined string error. If I take
it out, it works fine.
Here's sample code:
public void doGet (HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException{
PrintWriter out;
// set content type and other response header fields first
response.setContentType("t ext/html") ;
// then write the data of the response
out = response.getWriter();
// html text ........................
out.println("<SCRIPT language=\"JavaScript\">") ;
out.println("<!--");
out.println("function Warning(war, war1){");
out.println("if(war == \"\" || war1 == -1) {");
??? out.println("alert(\"1. Save As \n 2.Open \" );");
out.println("return (false);");
out.println("}");
out.println("else {");
out.println("return (true);");
out.println("} }");
out.println("//-->");
out.println("</SCRIPT>");
// html text...................... ...
}
servlet, and if I put a "\n" into my code -
I get a undetermined string error. If I take
it out, it works fine.
Here's sample code:
public void doGet (HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException{
PrintWriter out;
// set content type and other response header fields first
response.setContentType("t
// then write the data of the response
out = response.getWriter();
// html text ........................
out.println("<SCRIPT language=\"JavaScript\">")
out.println("<!--");
out.println("function Warning(war, war1){");
out.println("if(war == \"\" || war1 == -1) {");
??? out.println("alert(\"1. Save As \n 2.Open \" );");
out.println("return (false);");
out.println("}");
out.println("else {");
out.println("return (true);");
out.println("} }");
out.println("//-->");
out.println("</SCRIPT>");
// html text......................
}
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alert("1. Save As
2. Open");
instead of:
alert("1. Save As \n2. Open");