Averages Program

I am having a bit of a problem completing this task and i was hoping someone could help me! I'm only using simple pascal language. Heres the question:

Design a program that accepts numbers (ending with -999 as a rogue value) and the prints out the average and also each number input. Beside each number is the difference from the average (obtained by subtracting the average from it).

So theres the question! And heres the program i have done so far...except its not very good and doesn't work yet!! Also i have to use an array with VERY SIMPLE LANGUAGE!!! Heres my program:

Program Averages;
Uses Crt;

   numbers:array[1..100] of integer;

Procedure Main;
  writeln('Averages Program');

     For i:=1 to 10 {amount in list} do

  writeln('',number,' ',difference);
  writeln('The Average is ',average);


Please please could someone, anyone help me?!?!
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emmarichardsonAuthor Commented:
Adjusted points to 100
Simple enough? Is this what you want?

Program Averages;

uses crt;

var Numbers : array[1..100] of integer;
    Number  : integer;
    Sum     : longint;
    i,total : integer;
    Average : real;

 writeln('Average program   Enter -999 to exit');
 total := 0;
 i := 1;
  if Number <> -999 then begin
   Numbers[i] := Number;
 until (Number = -999) or (i > 100);

 if total > 0 then begin
  Average := Sum / total;
  Writeln('Average is : ',Average :0:2);
  For i := 1 to total do begin
   writeln(Numbers[i]:6,' - ',Average:0:2,' = ',(Numbers[i]-Average):9:2);
   if i mod 24 = 0 then readkey;
emmarichardsonAuthor Commented:
well, that program is ok, but the thing is that  i need to use simpler language.for example i don't use 'longint' or 'readkey'.
If you could leave these bits out and just stick to simple 'readln' etc.
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Well, you can replace all Readkey with Readln without a problem.

Longint can be replaced with integer... however, there might be an overflow so that the average value will not be correct. An Integer variable can hold any value from -32768..32767
Longint ,is a Long INTeger, wich can hold the values from -2147483648..2147483647,
So, as long as the total sum is less than 32767 you can use integer instead of longint without any problems.

you could also replace: writeln(Numbers[i]:6,' - ',Average:0:2,' = ',(Numbers[i]-Average):9:2); with
 writeln(Numbers[i],' - ',Average,' = ',Numbers[i]-Average);
But If you do, the real values will be written as exponetial values, 1.00000000E+1 for instance.

This line can be removed :
If i mod 24 = 0 then readkey;

Other than that I don't know how to make the code any simplier...

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emmarichardsonAuthor Commented:
Thanks, but what does the  (for example) 6 represent ?  (Numbers[i]:6,)
Numbers[i]:6 makes the write or writeln procedure to make the size of the variable at least 6 digits.
e.g. if Numbers[i] = 123 it has 3 digits, but since we pass :6 after the variable, it'll be considered to have 6 characters by write/writeln nomatterwhat the actual size is.

So if
Writeln(Numbers[i],'!'); would give the output:
Writeln(Numbers[i]:6,'!'); would give:
123   !

if you use :0:2 as we do when we write the average variable, :0 = the minimum number of characters in output, :2 = number of visible decimals in output!
emmarichardsonAuthor Commented:
Thanks for your help!
emmarichardsonAuthor Commented:
I've just tried out the program which you suggested and i have found that it does not work! At the last 'end' of the program it says its not complete! WHY?
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