• C

Rotate accumulator right using bitwise operators?

Basically I would like to know how to get the effect of RAR using
C bitwise operators.

e.g 1101 should become 1100

Can someone please help me.

Regards &  Thanks,
arut
arutAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

hongjunCommented:
What do you mean?
It's clockwise or anti-clockwise rotation?

1101 to become 1100? I assume it should be clockwise rotation right?

Please give more examples after you have read my comment so that I can help you.

hongjun
0
scrapdogCommented:
Assuming your "accumulator" contains n bits:

acc = ((acc&1)<<(n-1)) | (acc>>1);

So, if your accumulator contains 8 bits, this statement would be:

acc = ((acc&1)<<7) | (acc>>1);


If you wish to rotate your accumulator through a "carry bit":


acc = ((carry&1)<<7) | ((carry=acc)>>1);
carry=carry & 1;
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
C

From novice to tech pro — start learning today.