/var/log/messages....

Hi,

Found /var/log/messages

Nov 21 20:56:10 yippex popper[10646]: (v2.53) Unable to get canonical name of client, err = 0

Nov 21 20:56:11 yippex popper[10646]: @[202.188.212.40]: -ERR Too few arguments for the auth command.

Whats wrong, is it DNS problem ?
And how to fix it?

Thanx alot
qaz'
qazakaAsked:
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mnewnhamCommented:
Trying adding a Fully qualified host entry for the IP address of the connection in your /etc/hosts file as well as an unqualified name, e.g.

1.2.3.4    ppp    ppp.yourdomain.com

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qazakaAuthor Commented:
hi,

I still not very sure, why i have to add the IP ppp ppp.domain.com  ?

give me a hand

Thanx
qaz
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mnewnhamCommented:
Sorry, whaty I meant was.

1. Assume that you have a client that comes in from the IP address 202.188.212.40

2. The host name for this address is "foo".

3. Your local domain is "bar.com"


Try adding the following entry to /etc/hosts.

202.188.212.40 foo foo.bar.com
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qazakaAuthor Commented:
the IP for the client is a dynamic IP,
because he login to net using the phoneline.
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mnewnhamCommented:
Is the dynamic ip offered by the Linux system, or a RAS somewhere. In bothe cases, there is normally only a limited range of addresses offered. Add a hosts entry for every possible address that it could have.

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qazakaAuthor Commented:
No no..

What i mean is my client login to the internet through his local ISP, so the IP will be different when he disconnect and login again..
 
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mnewnhamCommented:
In that case, you need to configure DNS so that your Linux box can resolve the IP address
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qazakaAuthor Commented:
could you give me a more clearer way to solve it, what should i change into DNS?
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mnewnhamCommented:
in your /etc/resolv.conf, you should add the line:

nameserver  "your isp ns address"

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qazakaAuthor Commented:
i had added it already
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