Round() in VB5?

I am going back and forth from VB5 and 6.
But my problem is this: How do you use the round funciton in VB5?
as in
num=round(1.235,2)
num=1.24
LVL 2
jagoodieAsked:
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nutwissCommented:
there isn't a round() function in VB5.
it was added in vb6

you could try this equivalent:

Public Function Round(dbl As Double, dp As INteger) As Double
round = format(dbl, "#." & string(dp, "#")
End Function

(sorry this was written on the fly, forgive any mistakes)
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nutwissCommented:
BTW if you add any Global function to a VB project, with the same name as an existing VB function, then VB will use *YOUR* version in deference to the intrinsic function.

So... If you put the above code in a project, it will be used *both* in VB5 and VB6.
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jagoodieAuthor Commented:
Wow, that was fast.
Looks good.
Thanks a bunch.
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nutwissCommented:
no probs.
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jagoodieAuthor Commented:
why am i getting a type mis match?
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nutwissCommented:
Have you put the final bracket in? (I misesd it out)

The problem was that I had written "#.",which implies a digit otherwise nothing, meaning that - for example

 Round(0,x) = "."

the code was returning a string, whereas the function expected a double. Replacing "#." with "0." corrects the problem. "0" implies a digit otherwise zero.


This is copied directly from VB. It's tested!


Public Function Round(dbl As Double, dp As Integer) As Double
Round = Format(dbl, "0." & String(dp, "#"))
End Function
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jagoodieAuthor Commented:
yes, thank you. this works much better.
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Visual Basic Classic

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