My EDO RAM's size

I've got 2 of 72-pin EDO SIMM from my cousin's family a few moths ago. Each of them has 16 chips labeled:

9731 M7315-U

Now, they are installed in a "Supermicro P5MMS" mainboard. (I've lend them.) When the computer turn on, it shows 16000MB RAM. Can you tell me they are really 16MB SIMM, or they're just 8MB per piece (but the mobo can got only half of them)?
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Does it have anything on it like 2x32
2x36 or similar?

You have "only" 16 Mo. Just 8 Mo per piece.

Technical answer :

AS : Alliance Semiconductor
414405 : Memory configuration : 4*1Mb(one chip)  
60 : speed : 60ns
JC : Package : Plastic , SOJ
9731 : week 31 of 1997
20 pins ( 4 * 5).

Equivalent to HYB514405BJ (Siemens)

If you have 16 chips on SIMM :

16*(4*1Mb) = 64Mb without parity
64Mb=8Mo ( 1Mo = 8 Mb)
Note: 1 octet = 1 byte = 8 bits

Each simm => 8 Mo

2 simms -> 16 Mo

Note: bit <> byte - 1 octet = 1 byte = 8 bits.
Ram capacity :Mbit ...
You must divide by  8 to obtain Mo

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