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open a file for input

Posted on 2000-01-16
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Last Modified: 2010-05-18
Why does the following part of my script result in giving me the error message "COULDNT OPEN FILES.HTML":

#---BEGIN SAMPLE SCRIPT

$FULL_PATH = "D:\\webs\\websites\\URL.com\\cgi_html\\";

open (CONTENTS, "< $FULL_PATHfiles.html") || &CgiDie ("Couldn't open files.html");

#---END SAMPLE SCRIPT

I use the literal path because the URL path alone does not work at all with anything I use it for. I can open a file for OUTPUT but not an existing file for INPUT. My server admin says because they use a WINDOWS NT server that directly executes a PL file, I do not have to set permissions. I thought perhaps it might be something due to an illegal access attempt. Hope this error looks familiar to someone.
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Question by:microboard
3 Comments
 

Accepted Solution

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lorentg earned 400 total points
ID: 2357966
should these be \\ or / ?

And, more to the point you need:
${FULL_PATH}files.html

In this case you need this because it is looking for a variable with the name FULL_PATHfiles.html in your version and you really want the variable and then the literal.
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Expert Comment

by:ozo
ID: 2358215
#a more informative error message like
&CgiDie ("Couldn't open $FULL_PATHfiles.html because $!");
#might have revealed the problem
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Author Comment

by:microboard
ID: 2358389
lorentg, all I can say is THANKS!
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