IP Address command

I am looking for a command that will give me the IP address of the particular machie that I am on.  (Something like the hostname command)
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The first problem here is that not all machines have an IP address.  The second is that not all machines have only one IP address.

Meanwhile, the following ought to work on most Unix systems...

nslookup `hostname` | awk '
  /^Name:/ { flag=1 }
  flag && /^Address/ {
    gsub( /,/, "")
    for(i=2; i <= NF; i++)
      print $i

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ping -s <hostname> shud fetch you the ip address of the machine..
This will fetch an IP address of the machine, but will not fetch all IP addresses if there are more than one.  Of course, this may be good enough in some circumstances.  Meanwhile, you'll also want to make sure you have the right ping options for your particular platform.  For example, on HP-UX, you'd use

/usr/sbin/ping -s 1 -c 1 `hostname` | head -1 | cut -d '(' -f 2 | cut -d ')' -f 1
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Try ifconfig -a
This should give the IP addresses for each NIC thats in the server
Again, this depends on the Unix flavor.  On HP-UX, which does not have ifconfig -a, you'd need to do

lanscan | grep '^[0-9]' | awk '{print $5}' | while read dev
do      ifconfig "$dev"
done | grep inet | awk '{print $2}'
ifconfig -a is good to show the addresses, you can also try netstat -in to show the active interfaces and addresses assigned to them
Ah, hadn't tought of the netstat -in one.  Yes, that would work too.
  netstat -in | awk '$4 ~ /^[0-9]/ && $4 !~ /^127/ { print $4 }'

I don't know of any OS specific tweaking you'd need, but netstat, and it gives you all the IP's, so that makes it one of the better methods.
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Unix OS

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