winson
asked on
write to file problem
Referring to the code below
I have to run the code like
app.exe 1 23 8
so the value
argv[1] = 1
argv[2] = 23
argv[3] = 8
so what is the following code to and up let say add up
a) first two value
b) add all value
and write the two calculate value to a file
THANX IN ADVANCE
#include <iostream.h>
#include <stdio.h>
#include <string.h>
int main( int argc, char *argv[], char *envp[] )
{
char input[9];FILE *stream;
int iNumberLines = 0; // Default is no line numbers.
// If more than .EXE filename supplied, and if the
// /n command-line option is specified, the listing
// of environment variables is line-numbered.
if( argc == 2 && stricmp( argv[1], "/n" ) == 0 )
iNumberLines = 1;
// Walk through list of strings until a NULL is encountered.
for( int i = 0; envp[i] != NULL; ++i )
{
if( iNumberLines )
cout << i << ": " << envp[i] << "\n";
}
}
I have to run the code like
app.exe 1 23 8
so the value
argv[1] = 1
argv[2] = 23
argv[3] = 8
so what is the following code to and up let say add up
a) first two value
b) add all value
and write the two calculate value to a file
THANX IN ADVANCE
#include <iostream.h>
#include <stdio.h>
#include <string.h>
int main( int argc, char *argv[], char *envp[] )
{
char input[9];FILE *stream;
int iNumberLines = 0; // Default is no line numbers.
// If more than .EXE filename supplied, and if the
// /n command-line option is specified, the listing
// of environment variables is line-numbered.
if( argc == 2 && stricmp( argv[1], "/n" ) == 0 )
iNumberLines = 1;
// Walk through list of strings until a NULL is encountered.
for( int i = 0; envp[i] != NULL; ++i )
{
if( iNumberLines )
cout << i << ": " << envp[i] << "\n";
}
}
I'll tell you this much for now.
To write a number to a file you need to use an fstream object like so
#include <fstream>
using namespace std;
int main()
{
fstream File("thefilename",ios_bas
int X = 5;
File << X;
}
To write a number to a file you need to use an fstream object like so
#include <fstream>
using namespace std;
int main()
{
fstream File("thefilename",ios_bas
int X = 5;
File << X;
}
A bit more. The values to be added together are specified as parameters to the program in the argv[] array. This means the values are all character strings. i.e they are characters that express the value, not the binary representation of the value. i.e. the values are expresed like
char *AValue = "1999";
not like
int x = 1999;
The computer can't do math on a string anymore than you can do math like
"one + "five"
The strings need to be converted to the integer values they represent. (like you would convert "two" to 2). This can be done using the atoi() function.
If that doesn't help enough, try to ask more specific questions.
char *AValue = "1999";
not like
int x = 1999;
The computer can't do math on a string anymore than you can do math like
"one + "five"
The strings need to be converted to the integer values they represent. (like you would convert "two" to 2). This can be done using the atoi() function.
If that doesn't help enough, try to ask more specific questions.
ASKER CERTIFIED SOLUTION
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O , i see, nietod think , that it is hopework!
Winson, is it true?
Winson, is it true?
nu, after 'd', i see, that it is really
homework...
homework...
Do you have specific questions?
Do you have any work on this (incomplete even) that we can review?