A newbie question....

Posted on 2000-02-18
Medium Priority
Last Modified: 2010-04-15
I'm new to progamming in C. I've done extensive work in Perl which is pretty similar.

My problem is that I've got a loop that doesn't seem to be working right.

while (timein !=0 && timeout !=0) {
   execute code....

However, it seems to be quitting too early. If "timein = 0" it will stop OR if "timeout = 0" it will stop.

I need to only stop if both conditions are met. Do I have the syntax wrong?

Extra points for my stupidty :)

Question by:drummond

Expert Comment

ID: 2535866
try this, and lets see the code, maybe you are setting one when you don't want to..

while (! (timein==0 || timeout==0))
  execute code....
LVL 16

Accepted Solution

imladris earned 480 total points
ID: 2535872
I think your confusion lies in the while. The condition

timein!=0 && timeout!=0

will evaluate to true if both timein and timeout are nonzero. However, you want that to be your stopping condition. A while is defined as:

{   code

The while will continue to iterate executing code as long as condition evaluates to true.
As you can see your condition specifies when to stop, whereas the while expects it to specify the condition for continueing. So reversing it should suffice either:

while(timein==0 || timeout==0)


while(!(timein!=0 && timeout!=0))


Author Comment

ID: 2536489
You're right! Thank you!


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