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Date Subtraction

Posted on 2000-02-22
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Last Modified: 2011-09-20
I wish to enter a day date (e.g. 15) and have it subtracted by
another date that is also entered (in the same format).
It's a normal subtraction except when it goes over months.

eg.      2 March
      4 April
      -------
      33 Days      

P.S I'm using VB 6
Thanks
Dave Steers
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Comment
Question by:dsteers
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8 Comments
 
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Accepted Solution

by:
Éric Moreau earned 200 total points
ID: 2548740
DateDiff do it very easily.

msgbox datediff("d","march 2 2000", "april 4 2000")
0
 

Expert Comment

by:pinshah
ID: 2557165
if u have two dates use
datediff("d","march 2 2000", "april 4 2000")

else if u want to subtract or add days/months etc

use DateAdd
0
 
LVL 70

Expert Comment

by:Éric Moreau
ID: 2558573
pinshah,

You steal my comment! Change it to a comment now.

dsteers,

Is it working now?
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Author Comment

by:dsteers
ID: 2560192
Think so,
I'll try it out
Thanks
0
 

Author Comment

by:dsteers
ID: 2563685
Why Copy emoreau's Comment and post it as an answer.
Sorry
0
 

Author Comment

by:dsteers
ID: 2563693
Thanks emoreau,
Great help,
also (for another 50 points),
I was wondering if there is some sort of code that would allow subtraction of time,where the times are over two different days.
E.g. 1340 (PM) Wednesday 8 March
     0200 (AM) Thursday 9 March

The Code saying how many days,hours minutes between the two times.

Thanks

Dave Steers
0
 
LVL 70

Expert Comment

by:Éric Moreau
ID: 2564861
Try this:

Option Explicit

Private Sub Command1_Click()
Dim dtm1 As Date
Dim dtm2 As Date
Dim lngDiff As Long
Dim lngDays As Long
Dim lngHours As Long
Dim lngMinutes As Long

    dtm1 = "2000/03/08 13:40"
    dtm2 = "2000/03/09 2:00"
   
    'Returns number of minutes
    lngDiff = DateDiff("n", dtm1, dtm2)
   
    'Extract days
    If lngDiff > (24 * 60) Then
        lngDays = Int(lngDiff / (24 * 60))
        lngDiff = lngDiff - (lngDays * 24 * 60)
    End If
   
    'Extract Hours
    If lngDiff > 60 Then
        lngHours = Int(lngDiff / 60)
        lngDiff = lngDiff - (lngHours * 60)
    End If
   
    'Extract Minutes
    lngMinutes = lngDiff
   
    MsgBox "Difference between dates: " & _
           lngDays & " days, " & _
           lngHours & " hours and " & _
           lngMinutes & " minutes."
End Sub
0
 

Author Comment

by:dsteers
ID: 2571108
I'll Try it out.
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