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# detect a scalar

kitwei asked
on
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Last Modified: 2010-03-05
hi, is there a way to detect a scalar whether it contains numbers or char?

thx

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Commented:
if (\$Mystery =~ /^[0-9]+\$/) {
print "\$Mystery is a number\n";
} else {

print "\$Mystery is not a number\n";
}

Commented:
If you wanted to include numbers with a decimal point, the test would have to change to
if ((\$Mystery =~ /^[0-9]*.[0-9]*\$/) && (\$Mystery =~ /[0-9]/)) {

The test above checks that the variable contains at least one of the digits 0-9 and at most one decimal point and nothing else.

Commented:
Here is an interesting example:-

\$Var= "20";   # \$Var is a string
\$Var++;   # \$Var is being made to behave like a number

\$Var2 = "2" . "1";         # \$Var2 is two chars side by side
print "Equal\n" if (\$Var2 == \$Var);  # Trying to use \$Var2 as a _number_

# Result: Prints "Equal"
# Conclusion:  Perl works out whether you want the variable to be used as a number or a character string, and does the right thing.

Commented:
This one is on us!
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Commented:
What about "-3" ?

Commented:
Thanks, ozo.

if ((\$Mystery =~ /^[-+]?[0-9]*\.?[0-9]*\$/) && (\$Mystery =~ /[0-9]/)) {
to allow leading sign.

Commented:
I don't have access to try the code until monday, and I must try it that day. I promise I will respond.
Thank you very much.

Commented:
cool, everything I want, and more, thanks!
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Commented:
More than you wanted?  Does that mean you didn't want to accept "-3" as a number?

Commented:
no, I meant I appreciate all the information, it helps me learn perl

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