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detect a scalar

Posted on 2000-02-24
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Last Modified: 2010-03-05
hi, is there a way to detect a scalar whether it contains numbers or char?

thx

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Question by:kitwei
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10 Comments
 
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Expert Comment

by:PC_User321
ID: 2556404
if ($Mystery =~ /^[0-9]+$/) {
   print "$Mystery is a number\n";
} else {

   print "$Mystery is not a number\n";
}
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Expert Comment

by:PC_User321
ID: 2556466
If you wanted to include numbers with a decimal point, the test would have to change to
   if (($Mystery =~ /^[0-9]*.[0-9]*$/) && ($Mystery =~ /[0-9]/)) {

The test above checks that the variable contains at least one of the digits 0-9 and at most one decimal point and nothing else.
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LVL 5

Expert Comment

by:PC_User321
ID: 2556495
Here is an interesting example:-

$Var= "20";   # $Var is a string
$Var++;   # $Var is being made to behave like a number

$Var2 = "2" . "1";         # $Var2 is two chars side by side
print "Equal\n" if ($Var2 == $Var);  # Trying to use $Var2 as a _number_

# Result: Prints "Equal"
# Conclusion:  Perl works out whether you want the variable to be used as a number or a character string, and does the right thing.



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Accepted Solution

by:
PC_User321 earned 50 total points
ID: 2556534
Me again.

Correction: The search string for including decimal points should be

   if (($Mystery =~ /^[0-9]*\.?[0-9]*$/) && ($Mystery =~ /[0-9]/)) {
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LVL 84

Expert Comment

by:ozo
ID: 2556595
What about "-3" ?
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Expert Comment

by:PC_User321
ID: 2556629
Thanks, ozo.

   if (($Mystery =~ /^[-+]?[0-9]*\.?[0-9]*$/) && ($Mystery =~ /[0-9]/)) {
to allow leading sign.

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Author Comment

by:kitwei
ID: 2556853
I don't have access to try the code until monday, and I must try it that day. I promise I will respond.
Thank you very much.

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Author Comment

by:kitwei
ID: 2566633
cool, everything I want, and more, thanks!
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LVL 84

Expert Comment

by:ozo
ID: 2566688
More than you wanted?  Does that mean you didn't want to accept "-3" as a number?
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Author Comment

by:kitwei
ID: 2569537
no, I meant I appreciate all the information, it helps me learn perl
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