[Webinar] Streamline your web hosting managementRegister Today

x
?
Solved

How to create thread in UNUX

Posted on 2000-02-29
5
Medium Priority
?
190 Views
Last Modified: 2010-04-21
I would like to know how to create threads in UNIX systems using C/C++ with out nonstandard libraries and to obtain some example programs. How to run, stop and kill threads from parent process?
0
Comment
Question by:MaxZ
5 Comments
 
LVL 1

Accepted Solution

by:
hansendc earned 400 total points
ID: 2570088
Here is a fun little program that should get you started.  It uses the POSIX thread library, which is standard.  Do a "man pthread_create" on a UNIX system to get some good info.


#include <pthread.h>
#include <stdio.h>
#include <unistd.h>

int count;

void increment( int ntimes )
{
        for ( int i = 0; i < ntimes; i++ ) {
                int c;

                c = count;
                c = c + 1;

                count = c;
        }
}

int main( int argc, char ** argv )
{
        int n = 10000000;
        pthread_t t1, t2;
        pthread_attr_t attr;

        pthread_attr_init( &attr );
        pthread_attr_setscope(&attr, PTHREAD_SCOPE_SYSTEM);

        printf("Start Test. Final count should be %d\n", 2 * n );

        // Create threads
        pthread_create( &t1, &attr, (void * (*)(void *)) increment,
                        (void *) n);

        pthread_create( &t2, &attr, (void * (*)(void *)) increment,
                        (void *) n);

        // Wait until threads are done
        pthread_join( t1, NULL );
        pthread_join( t2, NULL );

        if ( count != 2 * n ) {
                printf("\n****** Error. Final count is %d\n", count );
                printf("****** It should be %d\n", 2 * n );
        }
        else {
                printf("\n>>>>>> O.K. Final count is %d\n", count );
        }
}
0
 
LVL 2

Expert Comment

by:curri
ID: 2585572
There is NO support for threads in standard C or standard C++. You can find several different 'standards' for threads (and probably the best is the posix one that is mentioned above)
0
 
LVL 1

Expert Comment

by:hansendc
ID: 2585630
While correct about not having it be a part of the language in C++ or C, neither is printf.  
MaxZ, has your question been answered?
0
 

Expert Comment

by:ramaswamys
ID: 2586672
You can find answers to your questions and a whole lot of other useful links at the  'The LinuxThreads Library' site (http://pauillac.inria.fr/~xleroy/linuxthreads/ ).

Ramaswamy
0
 

Author Comment

by:MaxZ
ID: 2586706
Thank you for your answer. It was exactly what I needed.
0

Featured Post

Free Tool: ZipGrep

ZipGrep is a utility that can list and search zip (.war, .ear, .jar, etc) archives for text patterns, without the need to extract the archive's contents.

One of a set of tools we're offering as a way to say thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Have you ever been frustrated by having to click seven times in order to retrieve a small bit of information from the web, always the same seven clicks, scrolling down and down until you reach your target? When you know the benefits of the command l…
The purpose of this article is to demonstrate how we can upgrade Python from version 2.7.6 to Python 2.7.10 on the Linux Mint operating system. I am using an Oracle Virtual Box where I have installed Linux Mint operating system version 17.2. Once yo…
The Relationships Diagram is a good way to get an overall view of what a database is keeping track of. It is also where relationships are defined. A relationship specifies how two tables connect to each other. As you build tables in Microsoft Ac…
Hi, this video explains a free download that you can incorporate into your Access databases, or use stand-alone for contact management. Contacts -- Names, Addresses, Phone Numbers, eMail Addresses, Websites, Lists, Projects, Notes, Attachments…
Suggested Courses

590 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question