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toupper()
Prototype: int toupper(int aChar);
Header File: ctype.h and stdlib.h
Explanation: toupper accepts a character as an argument (it actually accepts an integer, but the two are interchangeable) and will convert it to uppercase, and will return the uppercase character, in the form of an ASCII integer, and leave the parameter unchanged.
Example:
//Program creates char d, sets it equal to lowercase letter
//Converts it to uppercase and outputs it
#include <ctype.h>
#include <iostream.h>

int main()
{
char d;
cin>>d;
d=toupper(d);
cout<<d;
return 0;
}

1) From the above function, int toupper(int aChar). My understanding is it takes only int value only
but from the explaination, it can take char and integer value. Would somebody pls explain!
When I key in "a" , it will output" A". Howver when I key in integer value which is equavalent to small
alphabet a , 97 or hex value 61. This programs output shows 9 for integer value and 6 for hex value.
Why it didnt appear capital "A"

wytze

replace

char d;

with

int d;

You are not putting the value 97 in the char d but the '9'. There is no upper case for '9'. When you replace the char with int you are putting the value of a char 'a' which is 97 in the variable d and this will convert to 'A'

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nietod

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Barath122599

ASKER

Thank you very much

Babyworship

Sorry.

Since 97 is an acceptible number for char type variable.
So,why char d only receive 9 ? not 97?

Thanks

nietod

I don't understand.