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Scalar to command, arrays in hashes?

Posted on 2000-03-01
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Last Modified: 2010-03-05
I want to store a bunch of arrays, and then store a single array list with all of the other arrays inside.  So:

@arrayLists = ("dog","cat","rat");
@dog = ("fido", "rex", "king");
@cat = ("tabby", "Kitty", "Morris");
@rat = ("Ratbert", "Sam", "Rudy");

Is there a way to retrieve the values from dog, cat, and rat, by using the values in arraylists?

Also, could I store this all in a single hash?

%masterList = (dog => @dog, cat => ("tabby","rex","king") ...etc for rat)

How would I retrieve these values?

There's gotta be a way...

Raydot.
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Question by:Raydot
6 Comments
 
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Expert Comment

by:RobWMartin
ID: 2574314
You need to use array references in the case of the hash (which, by the way, seems like the best structure to use):


%masterList=(
  dog => ["fido","rex","king"],
  cat => ["tabby","fluffy","princess"],
);

print "My third dog is $masterList{'dog'}[2]\n";

would print

My third dog is king


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Accepted Solution

by:
RobWMartin earned 300 total points
ID: 2574325
I said use array references, but actually I used anonymous arrays.  Ultimately the same thing as far as the hash value is concerned.  This would be more of an example of an array reference:

@dogs=("rex","fido","king");

%masterList=(
   dog => \@dogs,
   ....
)

Otherwise, everything is the same.

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LVL 16

Expert Comment

by:maneshr
ID: 2574329
try this. with this you dont even need the masterlist hash!!

#!/usr/local/bin/perl

@arrayLists = ("dog","cat","rat");
@dog = ("fido", "rex", "king");
@cat = ("tabby", "Kitty", "Morris");
@rat = ("Ratbert", "Sam", "Rudy");

#%masterList = (dog => @dog, cat => @cat rat => @rat)

foreach $arr (@arrayLists){
  foreach(@$arr){
    print $_,"\t";
  }
  print "\n";
}
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Expert Comment

by:ozo
ID: 2574434
%masterList = map{$_,\@{$_}} @arrayLists;
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Expert Comment

by:maneshr
ID: 2577352
were you able to check the comments that were offered?

let us know :)
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Author Comment

by:Raydot
ID: 2583879
You guys are brilliant.  While ozo and man went above and beyond, RobW did answer first.  Thanks!
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