Lora
asked on
I/o problems
Help me to write a program that will print arbitary input in a sensible way.
As a minimum it should print non-graphic characters in octal or hexadecimal according to local custom and break long text lines.
As a minimum it should print non-graphic characters in octal or hexadecimal according to local custom and break long text lines.
marcjb
If you think that the input may contain non-graphic characters, just hexdump the file.
ASKER
Can You write this program , please
#include <stdio.h>
#include<ctype.h>
#include<string.h>
main()
{
FILE *f1,*f2;
char file[81],x;
char buffer[81];
int c;
printf("\nEnter the file Name ");
gets(file);
if ((f1 = fopen(file,"r"))==NULL)
{
puts("error");
exit(1);
}
c^=c;
while(!feof(f1))
{
x=fgetc(f1);
if (x=='\n')
{
buffer[c++] = x;
buffer[c] = NULL;
printf("%s",buffer);
c^=c;
}
else
{
buffer[c++] = isprint(x) ? x: '.';
if (c == 79)
{
buffer[c] = NULL;
puts(buffer);
c^=c;
}
}
}
fclose(f1);
getch();
}
#include<ctype.h>
#include<string.h>
main()
{
FILE *f1,*f2;
char file[81],x;
char buffer[81];
int c;
printf("\nEnter the file Name ");
gets(file);
if ((f1 = fopen(file,"r"))==NULL)
{
puts("error");
exit(1);
}
c^=c;
while(!feof(f1))
{
x=fgetc(f1);
if (x=='\n')
{
buffer[c++] = x;
buffer[c] = NULL;
printf("%s",buffer);
c^=c;
}
else
{
buffer[c++] = isprint(x) ? x: '.';
if (c == 79)
{
buffer[c] = NULL;
puts(buffer);
c^=c;
}
}
}
fclose(f1);
getch();
}
deighton changed the proposed answer to a comment
ASKER CERTIFIED SOLUTION
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
ASKER
Can You please tell me what this means
c^=c
c^=c
Yes indeed!
c ^= c is shorthand for
c = c ^ c
^ is the 'exclusive or operator' so in bitwise terms 0 0 and 1 1 become 0
it has the same effect as c = 0; when used the way I used it. (XOR of a number with itself has to give zero)
To be honest it might be bad practise, perhaps you'd be better off using c = 0;
c ^= c is shorthand for
c = c ^ c
^ is the 'exclusive or operator' so in bitwise terms 0 0 and 1 1 become 0
it has the same effect as c = 0; when used the way I used it. (XOR of a number with itself has to give zero)
To be honest it might be bad practise, perhaps you'd be better off using c = 0;