SQL - ORDER BY SUM()

Create a VIEW that contains the first select:

CREATE VIEW MyFirstView AS
  select A.name as Name, sum(B.value) as SumOfB from A,B
  where A.name=B.name
  group by A.name

(actual syntax may vary, since I am using SQL Server)

Now, in order for you to select everything sorting by the aggregate field, treat the VIEW as a regular table (all data is dynamic):

SELECT * FROM MyFirstView
ORDER BY SumOfB


Another option is to have a select inside another select (pretty much as a view), but I don't know if Interbase supports it. Anyway, it's like this:

SELECT Name, SumOfB FROM
   (select A.name as Name, sum(B.value) as SumOfB from A,B
  where A.name=B.name
  group by A.name
)
ORDER BY SumOfB


This doesn't work in all cases, but there's a pretty good chance IB supports it. Anyhow, the first approach (creating a VIEW) is still your best shot.

Yours,

Alex

Sorry, But both your solutions are not supported in interbase.

1.In a view I can't use a 'group by'
and
2.I can't 'select from (select ...'

I think that is a limitation of interbase.

The only 'solution' I found out is  to create a second table based on the query with the 'group by' and then open the table and with an order by the sum-field.

Unfortunalely this is a time-consuming operation.

I'm not sure about interbase 5, but this statement works in SQL Server7,

SELECT name, SUM(value) AS Total
FROM b
WHERE name IN
        (SELECT DISTINCT name
      FROM a)
GROUP BY name
ORDER BY Total


Dave.

sorry johnstoned but order by total does not work ininterbase

sorry for the delay.

Your solution works !
In fact, it's so simple, but I could not find this in any helpfile or book.

Thanks.