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# print a weeknumber in a textfield

How I'll able to print the current weeknumber on an Visual Basic application.

Example:
when teh date is 3 januari
the application must print week 1
in a textfield

Der Freak
0
FREAK
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1 Solution

Commented:
Private Sub Command1_Click()
Dim d As Date
Dim nWeek As Long
d = Now
nWeek = DatePart("ww", d)
MsgBox "Week " & CStr(nWeek)
End Sub
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Author Commented:
Thx...but I think the code is not 100%

I test it but he said that it's week 11
and it is week 10 now

???
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Senior DBACommented:
It depends on which standard you are using for week number.  In some locales, week numbers start on the first week of a year with more than 3 days in it (for accounting purposes, at least - this is, as I understand it, used primarily in some European countries.)

The simple answer has already been given.  A more complex answer to andle the above case would be something like this:

Function WeekNumber (ByVal Dt as Date) As Integer

Dim Week%, tmpDt
Dim YrDay1%, WeekOfs%

tmpDt = CVDate("01/01/" & Format(Dt,"yyyy"))  ' Get new years day
YrDay1 = DatePart("w", tmpDt) ' What day of week was New Years for the input date?

WeekOfs = (YrDay1 > 4) ' If 3 or less days in 1st week, WeekOfs = -1

Week = DatePart("ww", Dt) + WeekOfs
If Week = 0 Then Week = Weeknumber(tmpDt - 1)
WeekNumber = Week

End Function

This should give the correct week number for the European case.  Note:  Yes, the week number for Jan 1 - 3 can be week 53!
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Commented:
Erick37 supplied the correct function, but the optional third parameter must be used to determine which week is the first week in the year.

Depending on your locale, the first week of the year might be the first week in which 1/1 appears, or it might be the first week in which 1/4 appears, or it might be the first full week of the year.

I think for you the correct syntax would be:

Private Sub Command1_Click()
Dim d As Date
Dim nWeek As Long
d = Now
nWeek = DatePart("ww", d, 1)
MsgBox "Week " & CStr(nWeek)
End Sub

to specify other "first weeks" use the following constants:

1 first week contains 1/1
2 first week has at least the first four days of the year
3 first week is first full week.

Hope this helps.

Wes
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Senior DBACommented:
One more possibility:  If you are simply counting the number of seven day periods since Jan 1, then use:

Function WeekNumber(Dt as Date) As Integer

Dim tmpDt, Days%

tmpDt = CVDate("01/01/" & Format(Dt, "yyyy")
Days = DateDiff("d", tmpDt, Dt)
WeekNumber = Days Mod 7 + 1
End Function

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Senior DBACommented:
Well, poop - I hadn't ever read that part of the DatePart documentation!  Thanks for the information (we can all learn something new here, even if we think we know the answer).
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Commented:
Happy to help.

Note that the comment from bhess1 would certainly work, and if you want total control over the return that is probably the way to go.  But using DatePart() allows you to take advantage of built-in (fast!!) functions and constants.

Wes
0

Author Commented:
I think this is working

Private Sub Command1_Click()
Dim d As Date
Dim weekNummer As Long
d = Now
weekNummer = DatePart("ww", d)
MsgBox ("Week " & (weekNummer - 1))
End Sub
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Commented:
That won't work for a few days out of every week.  You might find out tomorrow that you are getting answers that indicate the previous week.  You really need to use that third argument:

weekNummer = DatePart("ww", d, 1)

Wes
0

Author Commented:
Private Sub Command1_Click()
Dim d As Date
Dim nWeek As Long
d = now
nWeek = DatePart("ww", d, 1)
MsgBox "Week " & CStr(nWeek)
End Sub

gives me as answer week 11
and it's week 10 at the moment
0

Commented:
My calendar says it is week 11 at the time.  How are you calculating the first week in the year?

1/1/2000 was a Saturday, so the first week of the year was exactly one day long.  If you are under the impression that the first week of the year is the first full week, then use the constant 3:

=DatePart("ww", d, 3)

Wes
0

Author Commented:
Private Sub Command1_Click()
Dim d As Date
Dim nWeek As Long
d = now
nWeek = DatePart("ww", d, 1)
MsgBox "Week " & CStr(nWeek)
End Sub

gives me as answer week 11
and it's week 10 at the moment
0

Commented:
Crap.

I was wrong.  The firstweek argument is the FOURTH argument.  You have to include a comma for the option third argument, which we won't include:

datepart("ww",date(),,3)

Will return week 10

datepart("ww",date(),,1)

returns week 11

Sorry about the mix-up

Wes
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Author Commented:
At my calender is sunday 2 januari 2000 the first day of week 1. I live in Holland....maybe is that the difference

=datePart("ww",d,3)

constant 3 gives also week 11 as answer.
grtz..
FREAK
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Author Commented:
Thank u very much Wesley...
This code is working 100% !!!
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