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Lowest number in @numbers

graemesandwell
on
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Last Modified: 2010-03-05
Hi!

There are numbers stored in the @numbers (for example - @numbers={2,4,1,6))

How do I search though the @numbers and look for the lowest avaible number (only whole numbers and no negtives) and assign the lowest number to $lowest.

So in this example, the number 3 would be stored in $lowest.

Thanks in advance!

Graeme Sandwell
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#!/usr/local/bin/perl


$numbers[0] = 2;

$numbers[1] = 1;

@sorted_numbers = sort { $a <=> $b } @numbers;

print $sorted_numbers[0];  #this is the lowest

Author

Commented:
Hi!

I tested the program (using @numbers=(2,4,1,6} and it just shows me the lowest number which is 1.  I need it to print the lowest AVAIABLE number (ie, the lowest number which isn't there).

Thanks!

Graeme
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Commented:
@numbers{@numbers} = ();
@available = grep{!exists$numbers{$_}}(1..(sort{$a<=>$b}@numbers)[-1]+1);
$lowest = @available[0];
@numbers{@numbers} = ();
@available = grep{!exists $numbers{$_}}(1..($#numbers+2));
$lowest = $available[0];
@numbers{@numbers} = ();
($lowest, $others) = grep {!exists $numbers{$_}}(1..$#numbers+2);

Author

Commented:
Hi!

It worked.  Thanks a lot for everyones help!

Graeme Sandwell
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