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For operator (), it must be a member because you need an object to place to the left of the (). &nbsp;Without that object you would have confussion, for example if you had<br />
<br />
int operator(int i) { return i +1; };<br />
<br />
int x = 1;<br />
int y = (int) x;<br />
<br />
does that code just cast an int to an int, which does nothing, or does it call that overloaded operator ()? &nbsp;You can't tell, but as a member function an object will always appear to the left of the parenthesis to make this clear.<br />
<br />
continues
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For operator (), it must be a member because you need an object to place to the left of the ().  Without that object you would have confussion, for example if you had

int operator(int i) { return i +1; };

int x = 1;
int y = (int) x;

does that code just cast an int to an int, which does nothing, or does it call that overloaded operator ()?  You can't tell, but as a member function an object will always appear to the left of the parenthesis to make this clear.

continues

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operator [] is simlar to (), agan it is to force you to put an object to the left of the []. &nbsp;Although in this case there would be no syntacitc confussions as <br />
<br />
int y = [x];<br />
<br />
is not currently legal.<br />
<br />
I'm not sure why operator -&gt; would have to have this restriction. &nbsp;it seems like it could be written as a non-member that takes a single parameter that must be a user-defined class type. &nbsp;<br />
<br />

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operator [] is simlar to (), agan it is to force you to put an object to the left of the [].  Although in this case there would be no syntacitc confussions as

int y = [x];

is not currently legal.

I'm not sure why operator -> would have to have this restriction.  it seems like it could be written as a non-member that takes a single parameter that must be a user-defined class type.  



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Hey thanks for answering my question. But I need some more help on this. Can you mail me on jamanat@usa.net? <br />
&nbsp;please....<br />

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Hey thanks for answering my question. But I need some more help on this. Can you mail me on jamanat@usa.net?
 please....


<div>
Why e-mail? &nbsp;Is there any reason you cannot ask here? &nbsp; Information posted here will be saved in EE's database for future queries.
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Why e-mail?  Is there any reason you cannot ask here?   Information posted here will be saved in EE's database for future queries.

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why c++ does not allow =,(),[],-&gt; to be overloaded as friend function?<br />

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why c++ does not allow =,(),[],-> to be overloaded as friend function?


function overloading

C++ is an intermediate-level general-purpose programming language, not to be confused with C or C#. It was developed as a set of extensions to the C programming language to improve type-safety and add support for automatic resource management, object-orientation, generic programming, and exception handling, among other features.