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Forcing landscape orientation

Posted on 2000-03-18
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Last Modified: 2013-11-20
How can I force Print Preview  to show a particular view in landscape orientation without user intervention?
(and Print to print it, naturally!)
Mike.
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Question by:mgordon
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5 Comments
 
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Accepted Solution

by:
Wyn earned 100 total points
ID: 2632625
Dllocate a device mode structure (DEVMODE) and indicate that the dvice is in landscape mode.
Print is just working with a print DC in the same way.

Continue.
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LVL 5

Expert Comment

by:Wyn
ID: 2632649
If you use MFC ,Use a CPrintDialog:

CPrintDialog PrintDialog(FALSE);
   
 
AfxGetApp()->GetPrinterDeviceDefaults(&PrintDialog.m_pd);

DEVMODE  FAR *lpDevMode  = (DEVMODE  FAR *)  
::GlobalLock(PrintDialog.m_pd.hDevMode);
//set mode
lpDevMode->dmOrientation = DMORIENT_LANDSCAPE;
 
::GlobalUnlock(PrintDialog.m_pd.hDevMode);

Then create a CDC and attach with PrinterDC:
  CDC DC;
  DC.Attach(PrintDialog.GetPrinterDC());
 
//Then set the document info
  DOCINFO di;
  CString strTitle;
  memset (&di,0,sizeof(DOCINFO));
  strTitle.LoadString (AFX_IDS_APP_TITLE);
  di.cbSize = sizeof(DOCINFO);
  di.lpszDocName = strTitle;
  strTitle.Empty();

//start the actual printing
  DC.StartDoc (&di);
  DC.StartPage ();

 
//printing here.....
DC.TextOut();

.......detach latter.

All..
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LVL 5

Expert Comment

by:Wyn
ID: 2632658
Here is working code to set landscape mode:

PrintDialog.m_pd.hDevMode = ::GlobalAlloc( GHND, sizeof(DEVMODE) );
  DEVMODE * devMode = (DEVMODE *) ::GlobalLock(     PrintDialog.m_pd.hDevMode );
  devMode->dmSize = sizeof(DEVMODE);
  devMode->dmOrientation = DMORIENT_LANDSCAPE;
  devMode->dmFields = DM_ORIENTATION;
  ::GlobalUnlock( devMode );  
0
 
LVL 5

Expert Comment

by:Wyn
ID: 2632677
Finally,this article will help you alot:

HOWTO: Modify Printer Settings with DocumentProperties()
http://support.microsoft.com/support/kb/articles/Q167/3/45.ASP
0
 

Author Comment

by:mgordon
ID: 2639348
For Wyn.
The first 7 lines of your 4.40 (first) answer did the trick wonderfully well.
Thanks, Mike Gordon.
0

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