procedure to find wage

company wage formula: \$100 +\$(employee's age) +\$(1 + 2 + 3....+years)

A 37 year old employee with six years would earn \$158 (that is, 100 + 37 + 21).  (the value 21 comes from 1 + 2 + 3 + 4 + 5 + 6)

I need a program that will receive as input one employee's name, age, and years and print the wage information. I've used the FINDPAY procedure. this procedure will need to calculate and print employee's name and wage information.

Here's what I got:

var name: string;
age: integer;
years: integer;
i: integer;

procedure FINDPAY (name: string;
age: integer;
years: integer;
i: integer);

var wage: integer;
begin
for i:= 1 to years
do
wage := \$100 + age + i;
writeln (name, ' \$', wage:5:1);
end; {FINDPAY}

begin {main}
name := 'Jack' ;
age := 54;
years := 32;
FINDPAY (name, age, years)
end.
Who is Participating?

x

Commented:
procedure FINDPAY (name: string; age: integer; years: integer);

var
wage : integer;
temp : integer;
begin
wage := 0;
for temp = 1 to years do
wage := wage + temp;
wage := 100 + age + wage;
writeln (name, ' \$', wage:5:1);
end; {FINDPAY}

Try the above procedure.  It's not tested but should work.
0

Author Commented:
Adjusted points from 30 to 40
0

Author Commented:
The procedure worked, but I now need it receive all employees.
0

Commented:
Post another question explaining what you want.  It's not quite clear enough.  Are you getting info from keyboard or file.  Whatever you will probably need to use records and an array of records to hold what you want.
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.