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procedure to find wage

Posted on 2000-03-20
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Last Modified: 2010-04-16
company wage formula: $100 +$(employee's age) +$(1 + 2 + 3....+years)

A 37 year old employee with six years would earn $158 (that is, 100 + 37 + 21).  (the value 21 comes from 1 + 2 + 3 + 4 + 5 + 6)

I need a program that will receive as input one employee's name, age, and years and print the wage information. I've used the FINDPAY procedure. this procedure will need to calculate and print employee's name and wage information.

Here's what I got:

var name: string;
      age: integer;
      years: integer;
      i: integer;

procedure FINDPAY (name: string;
                                 age: integer;
                                 years: integer;
                                  i: integer);

var wage: integer;
begin
    for i:= 1 to years
          do
              wage := $100 + age + i;
               writeln (name, ' $', wage:5:1);
end; {FINDPAY}

begin {main}
    name := 'Jack' ;
     age := 54;
    years := 32;
    FINDPAY (name, age, years)
end.
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Question by:kazooie21
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4 Comments
 

Author Comment

by:kazooie21
ID: 2638376
Adjusted points from 30 to 40
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LVL 50

Accepted Solution

by:
dbrunton earned 160 total points
ID: 2639037
procedure FINDPAY (name: string; age: integer; years: integer);

var
  wage : integer;
  temp : integer;
begin
  wage := 0;
  for temp = 1 to years do
    wage := wage + temp;
  wage := 100 + age + wage;
  writeln (name, ' $', wage:5:1);
end; {FINDPAY}

Try the above procedure.  It's not tested but should work.
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Author Comment

by:kazooie21
ID: 2642437
The procedure worked, but I now need it receive all employees.
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LVL 50

Expert Comment

by:dbrunton
ID: 2643399
Post another question explaining what you want.  It's not quite clear enough.  Are you getting info from keyboard or file.  Whatever you will probably need to use records and an array of records to hold what you want.
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