# easy array question

I have an array of 32 textboxes

txtName(0)
txtName(1)
TxtName(2).....TxtName(31)

Objective:If one(or many) of these textboxes' backcolor is yellow, then it should open form1 else it should open form 2.

This is my current code but it will only work(shows form1) if all of the 32 textboxes' backcolor is yellow.  How can I make it show form1 even if only 1 textbox is yellow?
--------------------------
If TxtName(Index).BackColor = &H80FFFF Then

form1.Show
Else

form2.Show

End If

-------------------

Thanks much
###### Who is Participating?

Commented:
these should all work but I dont see a need to go through every textbox. Once you find a match youre done.

Dim i As Integer
Dim Found As Boolean
Found = False
Do
If TxtName(i).BackColor= &H80FFFF Then
form1.Show
Found = True
End If
i = i + 1
Loop Until i = UBound(TxtName) Or Found = True

0

Commented:
Try this:

dim i as integer
dim bYellow as Boolean

bYellow = False
For i = 0 to Ubound(TxtName)
If TxtName(i).BackColor = &H80FFFF Then
form1.Show
bYellow = True
End If
next

if bYellow = False then
form2.Show
end if
0

Commented:
Dim x,Found
Found = False
For x = 0 to 31
If TxtName(x).BackColor = &H80FFFF Then
form1.Show
Found = True
Exit for
End if
Next x
If Found = False then
form2.show
End IF
0

Commented:
Hes got it..  except that I would have done ..

dim Found as Boolean
Found = false
for x% = 0 to 31
....

Anyway =)
0

Commented:
ptran2000. All these guys have given u the solution u required. What r u waiting for. Each one is a solution for the problem and the best being AzraSound for the loop runs only until the backcolor is found. U r done know. rate it guy
0

Senior Systems AnalystCommented:
Answering my first question here. I'm so excited :)  What form are you textboxes on. Here is code for 3 forms. replace names if you need to. Everybody let me know what you think.

Private Sub Command1_Click()
Dim sControl As Control

For Each sControl In form1
If TypeOf sControl Is TextBox And sControl.BackColor = &H80FFFF Then
Form2.Show
Exit Sub
End If
Next

If Form2.Visible = False Then
Form3.Visible = True
End If

End Sub
0

Commented:
Hello RandyB30. Welcome to EE!

As many others have already posted suggestions similar to your own would you mind retracting your answer and leaving it in as a comment?
0

Commented:
Let him be caraf_q. It is the author who has encouraged RandyB30 to post a diff. solution(atleast he thinks it is different) as the author haven't accepted the previous answers.
0

Commented:
But... the BIG disadvantage of randyb30's code is that form2 is loaded even if there is no need to. And you will get a fatal error if a control on your form does not a Backcolor property... I would recommend to use a somewhat optimized form of hes' code, something like...

Dim a As Integer

For a = txtName.LBound To txtName.UBound
If (txtName(a).BackColor = &H80FFFF) Then
Form2.Show
Exit For
End If
Next
If (a > txtName.UBound) Then Form3.Show
0

Commented:
<gah> of course it should be Form1.Show inside the For..Next loop and Form2.Show in the last line. ;)
0

Senior Systems AnalystCommented:
Sure, it's retracted. Maybe you should answer. Looks like you need points more than I.
0

Commented:
<blush>
AshokKumar, you're right. RandyB30 - apologies!
0

Commented:
Ptran2000. u r messing up with all those guys around here. Just go ahead and accept any one answer. What is taking you so much time. All are genuine solutions. Guys, pls. don't give any more version of answers to this guy.
0

Senior Systems AnalystCommented:
I see now that they are all comments. Doesn't matter Vbmaster caught the backcolor property mistake. Last answer from me.
0

Commented:
Hi ptran2000,

r u not satisfied with these expert's answer ?

Then why u r waiting ?

U need still more stuff ?

Rate the Expert.

0

Commented:
Whoa, give ptran a chance... the question was posted Thursday, March 23 2000 - 02:56AM GMT. It's now 11:34AM GMT. It is therefore fair to assume that ptran is in a different time zone and fast asleep at this stage <G>
0

Author Commented:
Thank you for all your responses, all were great. But, it is true what AzraSound said, "Once you find a match you're done"
0

Commented:
ptran2000, so does my solution,(only loop until a match is found) that is
0

Commented:
Yes, the solutions before azrasound where all stopping when a match was found.
0
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