• Status: Solved
• Priority: Medium
• Security: Public
• Views: 188

# date question

I need to write an if/else statement with the if being:

If current date is after the second sunday of march and before the second wednesday of june.......

I know how to do the basic if/else statement, but don't know how to write this 'if', could someone give me an example?

It needs to work annually, so year will not be included.

Thanks,

Chris
0
ChrisAndrews
1 Solution

Commented:
try the following: the time() function returns the seconds since 1970-01-01
then, you check the days from the eighth of march to the fourteenth of march of the year interesting you (current year?) by first calculating their time (in secs) and then using the date("l", \$time) function to  see whether it a "sunday" When you've  found the sunday, store its value, so the same for the interval in june, and then do
if (time()>\$start && time()>\$end) ...

hope this helps
maf
0

Commented:
This script  uses date math functions to work out  this info

I orginally wrote it to send remnders on the second and 4th
mondays of the month - so it's a bit of a hack :^)

I tried to tidy it up for you, but I think you'll get the idea... hope the text isn't wrapped by this form ...

<?

function GetTargetDate(\$monthnumber,\$target_day,\$target_day_occurrence) {
// where:
//      \$monthnumber=1 to 12 ; // march=3
//       \$target_day=0-6 ; // 0=sunday, 1=monday ...
//       \$target_day_occurrence - which day in the month (eg 2nd / 3rd monday )

\$oneday=86400 ; //seconds
\$now=time();
\$thisyear=date("Y",\$now);

\$firstofmonth=mktime(0,0,0,\$monthnumber,1,\$thisyear);
\$lastofmonth=mktime(0,0,0,\$monthnumber+1,1,\$thisyear); // first day of next month
\$lastofmonth=\$lastofmonth-\$oneday; // the day before (I love date math :^)

\$testday=\$firstofmonth; // start from day one
// find first "\$target_day" in this month (Sunday is daynumber 0)
do {
\$daynumber=date("w",\$testday);
\$testday += \$oneday; // next day
} while (\$daynumber!=\$target_day);

\$target_date=\$testday-\$oneday; // doh - we just went one day over of course.

\$target_date=\$target_date + ((\$oneday * 7) * (\$target_day_occurrence-1)) ;

return \$target_date;

}

// examples:
\$startdate=GetTargetDate(3,0,2);
print "<P> 2nd sunday in march is " . date( "d - M - Y",\$startdate) ;

\$finishdate=GetTargetDate(6,3,2);
print "<P> 2nd wednesday in june is " . date("d -M -Y",\$finishdate) ;

\$todaysdate=date("d",\$now);

if ((\$todaysdate <= \$startdate) && (\$todaysdate <= \$finishdate) ) {
// do whatever.
} //endif

?>
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.