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void pointer point to the class member?

Posted on 2000-04-05
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Last Modified: 2010-04-02
I define a void pointer p, a class A
I want p can point to the member in the A. How can I do it?
class A
{
public:
 int i1;
 char c1;
}
void A::*p[2];   //wrong when complie. :(
I hope can do this:
p[0]=&A::i1;
p[1]=&A::c1;
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Question by:kanyuchun
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12 Comments
 
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Accepted Solution

by:
Jan Louwerens earned 200 total points
ID: 2688357
you just have to do each one seperately. There is no automatic way to do it.

A aObj;
void* p[2];

p[0] = &(aObj.i1);
p[1] = &(aObj.c1);

you might need to cast the pointers to void to satisfy the compiler:

p[0] = (void*)&(aObj.i1);
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Expert Comment

by:GlennDean
ID: 2688418
jlouwere is right.  The only thing is i1 and c1 have to be public members.
   Glenn
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Expert Comment

by:GlennDean
ID: 2688425
Oops, forgot to mention that note jlouwere defined an actual object of class A.  
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Expert Comment

by:Jan Louwerens
ID: 2688434
yes, true, it can't be defined that way in a general case. The only way you could have it accessing class members without instantiating an object of that class is if those members are declared static.
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Expert Comment

by:nietod
ID: 2688498
A pointer to member pointer cannot safely be cast to type void and vice versa.  This is because a pointer-to-member is not necessarily a true pointer.

Now if you create an instance of A, you can make a void pointer that points to a data member in that instance of A, but that is not a pointer member.
0
 

Expert Comment

by:bsimmons
ID: 2688542
My comments will be in the /**/ style so that you can get a line-by-line idea of what you did wrong.

class A
{
public:
 int i1;
 char c1;
}

/*
Here you have said to the compiler "I want declare an array of 2 void pointers that is scoped inside of the A class."
No wonder the compiler screamed at you.
You can't use the scope operator (meaning the ::) unless you are referring to something that is already inside the class declaration.  You declared two variables: i1 and c1.
You can ONLY say A::i1 or A::c1.
*/
void A::*p[2];   //wrong when complie. :(

/* Here you have said, "Set the memory at index 0 in array p equal to the address of i1 which is scoped inside of the class A."
This too is wrong because you must first declare an instance of the a class.
*/
p[0]=&A::i1;
p[1]=&A::c1;


Here is how I would have written it given your class declaration:

   //Declare an instance of class A
   A Object;

   //Declare an array of void pointers
   void * p[2];

   //Set both indicies using class
   //notation
   p[0] = &Ojbect.i1;
   p[1] = &Object.c1;

That's it.

Good luck!!

Bryan
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Author Comment

by:kanyuchun
ID: 2688591
I have known about the void pointer already.
~(@_@)~
But I do not know how to accept both bsimmons' and jlouwere' answers. :-)
I satisfactory both your answer.
oh,what can I do? ;-)
How can I give bsimmons 100 points and give jlouwere 100 points ?
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Expert Comment

by:GlennDean
ID: 2688703
To me it is clear jlouwere gave the correct answer first (bsimmons basically rephrased jlouwere's answer).  You should of accepted his/her answer since it was correct.
  Glenn
0
 

Author Comment

by:kanyuchun
ID: 2688719
ok ,I receive jlouwere' answer.
bsimmons,thank you too. :-)
GleenDean,thank you too. :-)

Thank all !!!

~(@_@)~

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Author Comment

by:kanyuchun
ID: 2688727
thank you very much!
0
 

Expert Comment

by:bsimmons
ID: 2689508
My pleasure.  I was just trying to provide some detail.
0
 

Author Comment

by:kanyuchun
ID: 2689551
hi,bsimmons:

thank you for your explain which help me to know more about C.
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