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# need to change second value to minutes

Posted on 2000-04-07
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I previously posted a question on comparing 2 dates together to get a value that represents the differance.

I think I am getting closer to solving the problem but I still need help with one final part.

I need to track the time in minutes/seconds that a user has been on a page

I have 2 times one time is subtracted from the other and I am able to get a value of seconds or minutes.  The problem with minutes is that it is not acurate enough. I need the answer to show seconds also.  I can get the total second but then I cannot convert the seconds to show the time as minutes and seconds (output should look like this- 1:35)

Here is my code so far
<HTML>
<BODY>

<CFSET Variables.date1 = "07 Apr 12:39:56">
<CFSET Variables.date2 = "07 Apr 12:35:59">

<CFSET Variables.differenceSec = "#Abs(DateDiff("s", Variables.date1, Variables.date2))#">

The duration is <CFOUTPUT>#Variables.differenceSec#</CFOUTPUT>

</BODY>
</HTML>

When I divide the Variables.differenceSec by 60 I get the wrong answer it looks like this 3.6788784

How do I convert a number like 237 seconds to display the equivelent time in minutes and seconds?
0
Question by:jacqueschoquette
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1 Comment

LVL 2

Accepted Solution

paulkd earned 75 total points
ID: 2695240
<HTML>
<BODY>

<CFSET Variables.date1 = "07 Apr 12:39:56">
<CFSET Variables.date2 = "07 Apr 12:35:59">

<CFSET Variables.differenceSec = "#Abs(DateDiff("s", Variables.date1, Variables.date2))#">

<CFSET Minutes=int(Variables.differenceSec/60)>
<CFSET Seconds=(Variables.differenceSec mod 60)>

The duration is <CFOUTPUT>#Minutes# Minutes and #Seconds# Seconds.

</CFOUTPUT>

</BODY>
</HTML>
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