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searching file

How can I know if the person who uses my program has, let's say iexplore.exe on his computer? As I don't know where he could have insatalled it I must search the whole unit 'c:\' for this file, so my question here is how can i do that?

thanks.
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pin_plunder
Asked:
pin_plunder
1 Solution
 
edeyCommented:
you could try running a batch file with the line:

dir c:\iexplore.exe /s/b/p > c:\windows\temp\filesrch.txt

then look in:

c:\windows\temp\filesrch.txt

for a line containing iexplore.exe


GL
Mike
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xpherCommented:
listening
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pin_plunderAuthor Commented:
i'll try, but don't really like the idea, any other suggestions??
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kambizCommented:
You could find path of iexplore.exe in registry.

Root: HKEY_LOCAL_MACHINE
Key: Software\Microsoft\IE Setup\SETUP
Name: Path
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mathoughtCommented:
Try using findfirst..findnext to scan the drives.
By using findfirst/next for files with attribute of a directory and using ChDir you can recursivly scan through the drive's directories and in each directory use another findfirst..findnext (by calling another function for example) to look for files with the name of the file you are searching for.
Note that such a search can take time. Depending on the file you are looking for it might be better to search only in the PATH or search for a reference to it in the registry.

Hoped it helped...
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DiggieCommented:
do u want to search for a specific program (like iexplorer.exe) or the default program for a task (like default browser)?
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pin_plunderAuthor Commented:
the first thing, but i'm working on it. I'll try to use the windows registry.
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johnstonedCommented:
There is a registry key

HKEY_LOCAL_MACHINE\Software\Microsoft\Windows\Current Version\App Paths

there are lots of keys under this, each called by the name of an application installed on your computer.  Each key has a default value (containing the path of the exe and the exe name) and Path which contains the default "run in" directory.

If you look through these keys, you may find what you're looking for.

Dave.
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pin_plunderAuthor Commented:
thanks.
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