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And pls read<br />
<a href="http://www.eskimo.com/~scs/C-faq/q3.2.html" rel="ugc">http://www.eskimo.com/~scs/C-faq/q3.2.html</a><br />
<br />
This code is not well defined and can produce any result.
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And pls read
http://www.eskimo.com/~scs/C-faq/q3.2.html [http://www.eskimo.com/~scs/C-faq/q3.2.html]

This code is not well defined and can produce any result.

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An pls give a comment to your other question<br />
<a href="https://www.experts-exchange.com/jsp/qShow.jsp?ta=cprog&qid=10326206" rel="ugc">https://www.experts-exchange.com/jsp/qShow.jsp?ta=cprog&qid=10326206</a>&nbsp;
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An pls give a comment to your other question
https://www.experts-exchange.com/jsp/qShow.jsp?ta=cprog&qid=10326206 [https://www.experts-exchange.com/jsp/qShow.jsp?ta=cprog&qid=10326206] 

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You can't depend on a being incrementyed twice, because an object shall be modified at most once between sequence points.
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You can't depend on a being incrementyed twice, because an object shall be modified at most once between sequence points.

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why does the macro increment or decrement twice before it evalutes,when we pass a increment or decrement operator as a parameter?<br />
eg:#define macro(a) (a)*(a)<br />
<br />
in the main function<br />
&nbsp; &nbsp;macro(++a);
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why does the macro increment or decrement twice before it evalutes,when we pass a increment or decrement operator as a parameter?
eg:#define macro(a) (a)*(a)

in the main function
   macro(++a);

Macros

C is a general-purpose, imperative computer programming language, supporting structured programming, lexical variable scope and recursion, while a static type system prevents many unintended operations. By design, C provides constructs that map efficiently to typical machine instructions, so it has found lasting use in applications that had formerly been coded in assembly language, including operating systems as well as various application software for computers ranging from supercomputers to embedded systems. It is distinct from C++ (which has its roots in C) and C#, and many later languages have borrowed directly or indirectly from C.