Solved

Is there a equivalent of strncpy() in Java?

Posted on 2000-04-24
4
2,603 Views
Last Modified: 2008-03-06
I have to remove carraige return from the end of the String, is there a method to do that?

Thanks.
Theta.
0
Comment
Question by:theta
  • 2
4 Comments
 
LVL 16

Accepted Solution

by:
imladris earned 20 total points
ID: 2745393
Assuming, as your question implies, that you know the string ends with a carriage return, the simplest solution would be:

String ret; //string with \n in it
....
//ret gets a value somehow
....

String noret=ret.substring(0,ret.length()-1);

0
 
LVL 19

Expert Comment

by:Jim Cakalic
ID: 2745409
Perhaps you could use String.trim(). This returns a new String with all whitespace removed from both ends of the source String. Whitespace here is the same as defined by the Character.isSpace() method: horizontal tab, newline, form feed, carriage return, and, of course, space (' '). Remember that this returns a new String. Since String is an immutable object, you cannot change its contents.

    String s = <your string>
    s = s.trim();

If you want to just remove carriage return, you might consider something like:

    String s = <your string>
    int crIndex = s.indexOf("\r");
    s = s.substring(0, crIndex);

This will take a substring of the original String that contains everything from the beginning of the String up to but not including the index of the first carriage return character. Of course, everything after the carriage return is discarded as well.

If you really want to remove just carriage returns and leave everything else intact, you might consider this:

    String s = <your string>
    StringBuffer buf = new StringBuffer(s);
    for (int index = buf.length() - 1; index >= 0; --index) {
        if (buf.charAt(index) == '\r') {
            buf.deleteCharAt(index);
        }
    }
    s = buf.toString();

If you want to remove just the last occurrence of carriage return, break the loop after deleteCharAt().

There is also a rather inefficient way of doing it with StringTokenizer but I doubt that it would be necessary to go to that length.

Best regards,
Jim Cakalic
0
 
LVL 19

Expert Comment

by:Jim Cakalic
ID: 2745435
I was typing my comment when imladris posted so I didn't see his answer. Keep in mind that the carriage return and newline pair are usually seen in that order. As a result the posted answer will remove the last character from the String which is most likely going to be newline, not carriage return.

Playing around a little more, the simplest solution with the least side effects is likely to be String.replace():

    String s = <your string>
    s = s.replace('\r', '');

This will return a new String with all carriage returns removed.

Jim
0
 

Author Comment

by:theta
ID: 2745754
Imladris solution worked fine.

Jim, thankyou for such detailed description on strings. I tried your solutions and they worked too.

Theta.
0

Featured Post

Master Your Team's Linux and Cloud Stack!

The average business loses $13.5M per year to ineffective training (per 1,000 employees). Keep ahead of the competition and combine in-person quality with online cost and flexibility by training with Linux Academy.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

By the end of 1980s, object oriented programming using languages like C++, Simula69 and ObjectPascal gained momentum. It looked like programmers finally found the perfect language. C++ successfully combined the object oriented principles of Simula w…
Introduction This article is the last of three articles that explain why and how the Experts Exchange QA Team does test automation for our web site. This article covers our test design approach and then goes through a simple test case example, how …
Viewers will learn about the different types of variables in Java and how to declare them. Decide the type of variable desired: Put the keyword corresponding to the type of variable in front of the variable name: Use the equal sign to assign a v…
This video teaches viewers about errors in exception handling.

821 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question