I need assistance

What is it you are trying to do ?

Is the main function going to be void?

I need a lot more clarification on this, i'm getting 9 errors for reason's I don't know why.

You need a main function.  All standard C++ programs need a main.

This code (the for loops) needs to be in a function.  All code must appear in a function.  It could be placed in the the main function.

where would I put 'return hold at'?  I got two errors pointing to

int num[2][7] = {0,0};

is it because i'm not using 'num' in anything?


--------------------

#include <iostream.h>
#include <fstream.h>

//Function prototypes

void main()

//Declare and initialize array

int num[2][7] = {0,0};

int hold[2][7];

//Load 14 integers into aray
for (int x =0; x < 2; ++x)
{
     for (int y = 0; y < 5; ++y)
     {
         cout << "Please enter number for position (" << x << "," << y << "): ";
         cin  >> hold [x][y];
     }
}

would return hold  go down here?

>> where would I put 'return hold at'?  
Cdoes not let you pass and return arrays by value.  Which is what it seem you are trying to do.  The C way of dealing with this is for the caller to provide a pointer to an array and the function uses the pointer to fill in the array.  But I suspect you are not familiar with pointers yet.

>> would return hold  go down here?
Plus main() can only return an int,  so ther is no way (and no reason) for main() to return the array.

What do you want to do with the data that makes you want to return it?


You need to place the code in main's brackets, which you don't have, like

void main()
{
   //Declare and initialize array
   int num[2][7] = {0,0};

   *   *   *
}

how would I find the sum in that array?  All the numbers combined?

int main()
{

   for (int x =0; x < 2; ++x)
   {
      for (int y = 0; y < 7; ++y)
     {
        cout << "Please enter number for position (" << x << "," << y << "): ";
         cin  >> hold [x][y];
      }
   }

   int sum = 0;

   for (int x =0; x < 2; ++x)
      for (int y = 0; y < 7; ++y)
           sum = sum + hold[x][y];

   cout << "total: " << sum;

  return 0;
}

#include <iostream.h>
#include <fstream.h>

int hold[2][7];

void main()
{

int x;
int y;

for (x=0; x < 2; ++x)
{
     for (y=0; y < 5; ++y)
     {
         cout << "Please enter a number for position (" << x << "," << y << "): ";
         cin  >> hold [x][y];
     }
}

//Here you can output the array for example

}

slavik, have you read the question history?  You shouldn't answer with information that has already been posted.