?
Solved

Overloading the < operator

Posted on 2000-04-28
3
Medium Priority
?
167 Views
Last Modified: 2010-04-02
I get some weird error message saying:

E:\vc++\Private\StarDist\CFlexPoint.h(53) : error C2662: 'Y' : cannot convert 'this' pointer from 'const class CFlexPoint' to 'class CFlexPoint &'

when I try to overload the < operator..

WHAT IS WRONG???
THIS IS KILLING ME!!!
0
Comment
Question by:lar_jens
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
3 Comments
 
LVL 5

Expert Comment

by:proskig
ID: 2760486
Please post your code for this operator and its definition
0
 
LVL 22

Accepted Solution

by:
nietod earned 400 total points
ID: 2760594
it sounds like you declated operator < to be a const function, which it usually is, by including a "const" after the function's parameters, like the final "const" in

bool SomeClass::operator <(const SomeClass &Rht) const;

That is fine, in fact usually prefereable, but it means that the object that the function is invoked for must be treated as a constant object.  If you try to change the object, or try to call a non-constant member function (one that doesn't hae this "const" at the end), then you will get this error.

How to go about fixing the problem depends on details you haven't provided.
0
 
LVL 1

Author Comment

by:lar_jens
ID: 2761908
Thank you..
I solved my problem, and got wiser..

Couldn't get better...
0

Featured Post

New benefit for Premium Members - Upgrade now!

Ready to get started with anonymous questions today? It's easy! Learn more.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Introduction This article is a continuation of the C/C++ Visual Studio Express debugger series. Part 1 provided a quick start guide in using the debugger. Part 2 focused on additional topics in breakpoints. As your assignments become a little more …
Many modern programming languages support the concept of a property -- a class member that combines characteristics of both a data member and a method.  These are sometimes called "smart fields" because you can add logic that is applied automaticall…
The viewer will learn how to pass data into a function in C++. This is one step further in using functions. Instead of only printing text onto the console, the function will be able to perform calculations with argumentents given by the user.
The viewer will be introduced to the technique of using vectors in C++. The video will cover how to define a vector, store values in the vector and retrieve data from the values stored in the vector.

765 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question