Want to protect your cyber security and still get fast solutions? Ask a secure question today.Go Premium

x
Solved

# syntax

Posted on 2000-05-01
Medium Priority
207 Views
I get this error...

cc: Warning: numday.c, line 33: In this statement, "*total" of type "int", is be
ing converted to "pointer to int".
*total=31+numday(month-1, day, *total);
----------------------------------^
cc: Warning: numday.c, line 35: In this statement, "*total" of type "int", is be
ing converted to "pointer to int".
*total=30+numday(month-1, day, *total);
----------------------------------^

With the problem in this part of the code...

int numday(int month, int day, int *total)
{

if(month==1)
*total=day;
else if(month==2)
*total=28+day;
else
{
if(month==3||month==5||month==7||month==8
||month==10||month==12)
*total=31+numday(month-1, day, *total);
else
*total=30+numday(month-1, day, *total);
}

}

void printresults(int total, int month, int day)
{
printf("%d/%d is day %d of the year.", month, day, total);
}

int main(void)

{
int month, day, total;

getdata(&month, &day);

numday(month, day, &total);

printresults(total, month, day);

}

0
Question by:SaraBiz
1 Comment

LVL 1

Accepted Solution

jasonf earned 200 total points
ID: 2768149
In the recursive call to numday you are dereferencing total and passing its value.  Your function prototype, however, wants you to pass an address where the data resides.  In other words, don't dereference total in the argument list in the recursive calls to numday.  That should work.

Look at the error, then think about what it is saying...I will break it down for you.

The error is:
cc: Warning: numday.c, line 33: In this statement, "*total" of type "int", is being converted to "pointer to int".

The line of code where the error occurs:
*total=31+numday(month-1, day, *total);

The prototype for the function numday:
int numday(int month, int day, int *total)

What does *total refer to?  It is the value in the memory location addressed by the value of total.  That value happens to be an int.

Now look at the 3rd argument in the prototype for numday.  It is looking for a pointer to int, in other words an address.  When you look at the value stored at that address it has to be an int (hence 'pointer to int').  Do you now see why you are getting the error you are getting?

Hope this helps and hope my explanation clears up some of the confusion with passing pointers to functions and what the notation means.

Jason
0

## Featured Post

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Have you thought about creating an iPhone application (app), but didn't even know where to get started? Here's how: ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ Important pre-programming comments: I’ve never tri…
Examines three attack vectors, specifically, the different types of malware used in malicious attacks, web application attacks, and finally, network based attacks.  Concludes by examining the means of securing and protecting critical systems and inf…
The goal of this video is to provide viewers with basic examples to understand and use while-loops in the C programming language.
The goal of this video is to provide viewers with basic examples to understand how to create, access, and change arrays in the C programming language.
###### Suggested Courses
Course of the Month10 days, 3 hours left to enroll