Solved

Dynamic Picture box, button...

Posted on 2000-05-03
3
181 Views
Last Modified: 2010-05-02
Hi Experts,

  Can I check with you whether I can display picture boxes, buttons, label dynamically, that means I display them according to the number of records in my database.
is it possible ?
if yes, can show me some simple code on how to ?

Thanks
0
Comment
Question by:seahpc
3 Comments
 
LVL 43

Accepted Solution

by:
TimCottee earned 100 total points
ID: 2772967
The simplest method of this is to add one of each control to your form, set the index property to 0, (zero, not blank). You can then load additional elements of the control array using the load statement.

Here is an example:

rstData.MoveFirst
For intCount = 1 To rstData.RecordCount - 1
  Load txtText(intCount)
  txtText(intCount).Left = 100
  txtText(intCount).Top = 100 + 200 * intCount
  txtText(intCount).Text = rstData!TextField
  txtText(intCount).Visible = True
  Load lblLabel(intCount)
  lblLabel(intCount).Left = 2500
  lblLabel(intCount).Top = 100 + 200 * intCount
  lblLabel(intCount).Caption = rstData!LabelField
  lblLabel(intCount).Visible = True
  rstData.MoveNext
Next

To Clear Down:

rstData.MoveFirst
For intCount = 1 To rstData.RecordCount - 1
  Unload txtText(intCount)
  Unload lblLabel(intCount)
  rstData.MoveNext
Next
0
 
LVL 9

Expert Comment

by:Dalin
ID: 2772993
Surely you can.
Using controlArray.

After you open your recordset (say you call it MyRS), check how many record you have. Then use Load to add more picturebox, label and buttons.
At design time, you put one of each in your form. say you call it MyPic, MyBut, and MyLab. set the Index property to 0.

add the code to create the array
With MyRS
If .EOF = False then
     .MoveLast
     .MoveFirst
     MyLab(0).Caption = !somefieldName
     MyBut(0).caption = !SomeFieldName
     MyPic(0).Picture = Whatever
     If .RecordCount > 1 then
             For i   = 1 to .RecordCount -1
                   .MoveNext
                   Load MyLab(i)
                   Load MyBut(i)
                   Load MyPic(i)
                    MyLab(i).Caption = !somefieldName
                     MyBut(i).caption = !SomeFieldName
                    MyPic(i).Picture = Whatever
                  'set the position in the form
                   MyLab(i).Left = whatever
                   MyLab(i).Top = whatever
                  ...
               Next i
         End If
End With






0
 
LVL 28

Expert Comment

by:AzraSound
ID: 2774141
an alternative to creating a control array:

http://support.microsoft.com/support/kb/articles/Q190/6/70.ASP?LNG=CAN&SA=&FR=0

it also allows you to add controls that arent on your form to begin with

0

Featured Post

Live: Real-Time Solutions, Start Here

Receive instant 1:1 support from technology experts, using our real-time conversation and whiteboard interface. Your first 5 minutes are always free.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
Excel VBA combine two working workbooks 8 53
Put text in a picture ASP.NET C# 2 56
Run code from text file in vb 1 64
Microsoft Access combo box help 2 45
There are many ways to remove duplicate entries in an SQL or Access database. Most make you temporarily insert an ID field, make a temp table and copy data back and forth, and/or are slow. Here is an easy way in VB6 using ADO to remove duplicate row…
This article describes some techniques which will make your VBA or Visual Basic Classic code easier to understand and maintain, whether by you, your replacement, or another Experts-Exchange expert.
Get people started with the process of using Access VBA to control Excel using automation, Microsoft Access can control other applications. An example is the ability to programmatically talk to Excel. Using automation, an Access application can laun…
Get people started with the utilization of class modules. Class modules can be a powerful tool in Microsoft Access. They allow you to create self-contained objects that encapsulate functionality. They can easily hide the complexity of a process from…

776 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question